我正在尝试转换
static char bufferTR[] = "1645";
像这样的事情......
struct tm *tick_time = localtime(&temp);
在此函数中使用...
difftime(time_t end, time_t beginning)
这将为我提供两者之间的时间(以秒为单位),作为双倍。
任何帮助将不胜感激。
更新了代码...
#include <stdio.h>
#include <time.h>
static void update_time() {
// Get a tm structure
time_t temp = time(NULL);
struct tm *tick_time = localtime(&temp);
// Create a long-lived buffer
//static char buffer[] = "00";
char buffer[80];
static char buffer2[] = "00";
static char buffer3[] = "Xxx Xxx 00"; //Day of Week, Month, Date
strftime(buffer3, sizeof(buffer3), "%a %b %e", tick_time);
// Write the current hours and minutes into the buffer
if(clock_is_24h_style() == true) {
// Use 24 hour format
strftime(buffer, sizeof("00"), "%M", tick_time);
strftime(buffer2, sizeof("00"), "%H", tick_time);
}
else {
// Use 12 hour format
strftime(buffer, sizeof("00"), "%M", tick_time);
strftime(buffer2, sizeof("00"), "%I", tick_time);
}
//https://sourceware.org/newlib/libc.html#Timefns
static char bufferTR[6] = "1645";
time_t beginning;
struct tm info;
int hh;
int mm;
int minutediff = 1;
if (sscanf(bufferTR, "%2d%2d", &hh, &mm) == 2) {
printf("hh %d mm %d\n", hh, mm);
info.tm_year = 2001 - 1900;
info.tm_mon = 7 - 1;
info.tm_mday = 4;
info.tm_hour = hh;
info.tm_min = mm;
info.tm_sec = 1;
info.tm_isdst = -1;
beginning = mktime(&info);
if( beginning == -1 )
{
printf("Error: unable to make time using mktime\n");
}
else
{
strftime(buffer, sizeof(buffer), "%c", &info );
}
time_t end;
struct tm info2;
char buffer2[80];
info2.tm_year = 2001 - 1900;
info2.tm_mon = 7 - 1;
info2.tm_mday = 4;
info2.tm_hour = hh;
info2.tm_min = mm+minutediff;
info2.tm_sec = 1;
info2.tm_isdst = -1;
end = mktime(&info2);
if( end == -1 )
{
printf("Error: unable to make time using mktime\n");
}
else
{
strftime(buffer2, sizeof(buffer2), "%c", &info2 );
}
printf("%f", difftime(end, beginning));
}
// Display this time on the TextLayer
text_layer_set_text(s_time_layer, buffer);
text_layer_set_text(s_time_layer2, buffer2);
text_layer_set_text(s_time_layer3, buffer3);
text_layer_set_text(s_temp_layer, bufferTR);
text_layer_set_text(s_temp_layer2, buffer2);
}
最佳答案
我假设您想要 16:45 和 16:45 + x 之间的差值。
假设差异为 x=1 分钟int 分钟diff = 1;
。然后我们就可以在不同类型之间进行转换。
#include <stdio.h>
#include <time.h>
int main ()
{
static char bufferTR[5] = "1645";
time_t beginning;
struct tm info;
char buffer[80];
int hh;
int mm;
int minutediff = 1;
if (sscanf(bufferTR, "%2d%2d", &hh, &mm) == 2) {
printf("hh %d mm %d\n", hh, mm);
info.tm_year = 2001 - 1900;
info.tm_mon = 7 - 1;
info.tm_mday = 4;
info.tm_hour = hh;
info.tm_min = mm;
info.tm_sec = 1;
info.tm_isdst = -1;
beginning = mktime(&info);
if( beginning == -1 )
{
printf("Error: unable to make time using mktime\n");
}
else
{
strftime(buffer, sizeof(buffer), "%c", &info );
}
time_t end;
struct tm info2;
char buffer2[80];
info2.tm_year = 2001 - 1900;
info2.tm_mon = 7 - 1;
info2.tm_mday = 4;
info2.tm_hour = hh;
info2.tm_min = mm+minutediff;
info2.tm_sec = 1;
info2.tm_isdst = -1;
end = mktime(&info2);
if( end == -1 )
{
printf("Error: unable to make time using mktime\n");
}
else
{
strftime(buffer2, sizeof(buffer2), "%c", &info2 );
}
printf("difftime %f ", difftime(end, beginning));
}
return(0);
}
输出
hh 16 mm 45
difftime 60.000000
关于c - Pebble C 将 char 转换为时间以在 double difftime(time_t end, time_t begin) 中使用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37337954/