php - 使用php从文本中提取单词

Question

你好 friend 有一个小问题。我只需要提取文本“任何人”中的单词。

我尝试使用 strtok()、strstr() 检索单词。一些正则表达式，但只能提取一些单词。

由于单词可以伴随的字符和符号的数量，问题很复杂。

示例文本中必须提取的单词。这是一个示例文本:

Main article: our 46,000 required, !but (1947-2011) mail@server.com March 8, 2014 Gutenberg's 34-DE 'a' 3,1415 Us: @unknown n go http://google.com or www.google.com and http://www.google.com (r) The 509th "composite" and; C-54 #dog v4.0 ¿as is done? ¿article... agriculture? x ¿cat? now! Hi!! (87 meters).

Sample text, for testing.

提取文本的结果应该是:

Main article our required but March Gutenberg's a go or and The composite and dog as is done article agriculture cat now Hi meters

Sample text for testing

我写的第一个函数是为了方便工作

function PreText($text){
  $text = str_replace("\n", ".", $text);
  $text = str_replace("\r", ".", $text);

  $text = str_replace("'", "", $text);
  $text = str_replace("?", "", $text);
  $text = str_replace("¿", "", $text);
  $text = str_replace("(", "", $text);
  $text = str_replace(")", "", $text);
  $text = str_replace('"', "", $text);
  $text = str_replace(';', "", $text);
  $text = str_replace('!', "", $text);
  $text = str_replace('<', "", $text);
  $text = str_replace('>', "", $text);
  $text = str_replace('#', "", $text);

  $text = str_replace(",", "", $text);

  $text = str_replace(".c", "", $text);
  $text = str_replace(".C", "", $text);
  return $text;
}

拆分功能:

function SplitWords($text){
  $words = explode(" ", $text);
  $ContWords = count($words);

  for ($i = 0; $i < $ContWords; $i++){
    if (ctype_alpha($words[$i])) {
      $NewText .= $words[$i].", ";
    }
  }
  return $NewText;
}

程序:

<?
  include_once ('functions.php');

  $text = "Main article: our 46,000 ...";
  $text = PreText($text);
  $text = SplitWords($text);
  echo $text;
?>

是不是代码长了点。感谢您的帮助。

Answer 1

如果我没理解错的话，你想从字符串中删除所有非字母。我会用 preg_replace

$text = "Main article: our 46,000...";
$text = preg_replace("/[^a-zA-Z' ]/","",$text);

这应该删除所有不是字母、撇号或空格的内容。