我是并行编程的初学者,我尝试使用 pthread 库编写并行程序。我在 8 处理器计算机上运行该程序。问题是,当我增加 NumProcs
时,每个线程都会变慢,尽管它们的任务总是相同的。有人可以帮我弄清楚发生了什么吗?
`
#define MAX_NUMP 16
using namespace std;
int NumProcs;
pthread_mutex_t SyncLock; /* mutex */
pthread_cond_t SyncCV; /* condition variable */
int SyncCount; /* number of processors at the barrier so far */
pthread_mutex_t ThreadLock; /* mutex */
// used only in solaris. use clock_gettime in linux
//hrtime_t StartTime;
//hrtime_t EndTime;
struct timespec StartTime;
struct timespec EndTime;
void Barrier()
{
int ret;
pthread_mutex_lock(&SyncLock); /* Get the thread lock */
SyncCount++;
if(SyncCount == NumProcs) {
ret = pthread_cond_broadcast(&SyncCV);
assert(ret == 0);
} else {
ret = pthread_cond_wait(&SyncCV, &SyncLock);
assert(ret == 0);
}
pthread_mutex_unlock(&SyncLock);
}
/* The function which is called once the thread is allocated */
void* ThreadLoop(void* tmp)
{
/* each thread has a private version of local variables */
long threadId = (long) tmp;
int ret;
int startTime, endTime;
int count=0;
/* ********************** Thread Synchronization*********************** */
Barrier();
/* ********************** Execute Job ********************************* */
startTime = clock();
for(int i=0;i<65536;i++)
for(int j=0;j<1024;j++)
count++;
endTime = clock();
printf("threadid:%ld, time:%d\n",threadId,endTime-startTime);
}
int main(int argc, char** argv)
{
pthread_t* threads;
pthread_attr_t attr;
int ret;
int dx;
if(argc != 2) {
fprintf(stderr, "USAGE: %s <numProcesors>\n", argv[0]);
exit(-1);
}
assert(argc == 2);
NumProcs = atoi(argv[1]);
assert(NumProcs > 0 && NumProcs <= MAX_NUMP);
/* Initialize array of thread structures */
threads = (pthread_t *) malloc(sizeof(pthread_t) * NumProcs);
assert(threads != NULL);
/* Initialize thread attribute */
pthread_attr_init(&attr);
pthread_attr_setscope(&attr, PTHREAD_SCOPE_SYSTEM); // sys manages contention
/* Initialize mutexs */
ret = pthread_mutex_init(&SyncLock, NULL);
assert(ret == 0);
ret = pthread_mutex_init(&ThreadLock, NULL);
assert(ret == 0);
/* Init condition variable */
ret = pthread_cond_init(&SyncCV, NULL);
assert(ret == 0);
SyncCount = 0;
Count = 0;
/* get high resolution timer, timer is expressed in nanoseconds, relative
* to some arbitrary time.. so to get delta time must call gethrtime at
* the end of operation and subtract the two times.
*/
//StartTime = gethrtime();
ret = clock_gettime(CLOCK_MONOTONIC, &StartTime);
for(dx=0; dx < NumProcs; dx++) {
/* ************************************************************
* pthread_create takes 4 parameters
* p1: threads(output)
* p2: thread attribute
* p3: start routine, where new thread begins
* p4: arguments to the thread
* ************************************************************ */
ret = pthread_create(&threads[dx], &attr, ThreadLoop, (void*) dx);
assert(ret == 0);
}
/* Wait for each of the threads to terminate */
for(dx=0; dx < NumProcs; dx++) {
ret = pthread_join(threads[dx], NULL);
assert(ret == 0);
}
//EndTime = gethrtime();
ret = clock_gettime(CLOCK_MONOTONIC, &EndTime);
printf("Time = %ld nanoseconds\n", EndTime.tv_nsec - StartTime.tv_nsec);
pthread_mutex_destroy(&ThreadLock);
pthread_mutex_destroy(&SyncLock);
pthread_cond_destroy(&SyncCV);
pthread_attr_destroy(&attr);
return 0;
}
最佳答案
期待您的观察。
通常影响这种情况(worker 在本地计算上旋转)的主要因素是:
- nb_threads/nb_available_machine_cores 的比率
- 各线程的亲和度
这里的最佳情况是比率为 1,并且每个线程都与其中一个核心具有独特的亲和性。
这个想法是最大化每个核心的吞吐量。您可以通过在每个核心上运行一个且只有一个线程来实现这一点。如果增加线程数(比率 > 1),多个线程将共享同一个核心,迫使内核(通过任务调度程序)在每个线程的执行之间切换。这就是您观察到的。
每次内核必须操作这样的切换时,您都会为上下文切换付出代价。它可能会成为明显的开销。
注意:
您可以使用 pthread_setaffinity设置线程的亲和性。
关于c++ - Pthread 程序运行速度随着线程的增加而变慢,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23962108/