我需要做的就是将输入的全名字符串解析为 3 个独立的名称,这样我就可以获取每个名称的首字母并打印出来。谁能指出我正确的方向?
#include <iostream>
#include <string>
#include <fstream>
#include <iomanip>
using namespace std;
int main()
{
string [parsed_output] = fullName.split(" ");
string firstName = parsed_output[0];
string middleName = parsed_ouput[1];
string lastName = parsed_output[2];
string fullName;
char firstLetter = firstName[0];
char middleLetter = middleName[0];
char lastLetter = lastName[0];
cout << "Enter your first name, middle name or initial, and last name separated by spaces: \n";
cin >> fullName;
cout << "Your initials are: " << firstLetter << middleLetter << lastLetter << '\n';
cout << "Your name is: " << firstName << " " << middleName << " " << lastName << '\n';
return 0;
}
最佳答案
你让事情变得复杂了。 “parsed_output[0];”是什么意思?还有“全名”吗?你可以这样做:
#include <iostream>
#include <string>
#include <fstream>
#include <iomanip>
using namespace std;
int main()
{
string firstName, middleName, lastName;
cout << "Enter your first name, middle name or initial, and last name separated by spaces: \n";
cin >> firstName >> middleName >> lastName;
char firstLetter = firstName[0];
char middleLetter = middleName[0];
char lastLetter = lastName[0];
cout << "Your initials are: " << firstLetter << middleLetter << lastLetter << '\n';
cout << "Your name is: " << firstName << " " << middleName << " " << lastName << '\n';
return 0;
}
整点std::cin
也就是说,您获得了一个流,以使用提取运算符“>>”分隔的标记。如果您想手动提取名字、中间名和姓氏(如 hasans 答案),那么您首先需要整个字符串(一个包含所有 3 个名称和空格作为限制符的字符串)。要读取包含空格的输入,您可以使用 std::getline(std::cin, fullName)
而不是 std::cin
,因为 std::cin
将提取输入,直到遇到第一个尾随空格。
关于C++ 将输入字符串解析为变量,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19767644/