我正在尝试合并 R 中的两个 data.frame，以便 test_1 中的值(如果 test_2 中存在)会被覆盖
每次我尝试加入/合并它们时，我都会得到一堆 NA。
我无法为 if.na 制定一个简单的逻辑，然后使用 test_2。这是我需要做的，还是有更简单的方法？
test_1 = structure(list(rn = c("Red", "Blue",
"Green", "Yellow", "Pink", "Gold"
), X2022.08.01 = c(0, 0, 0, 0, 0, 0), X2022.08.02 = c(0, 0, 0,
0, 0, 0), X2022.08.03 = c(0, 0, 0, 0, 0, 0), X2022.08.04 = c(0,
0, 0, 0, 0, 0), X2022.08.05 = c(0, 0, 0, 0, 0, 0), X2022.08.08 = c(0,
0, 0, 0, 0, 0), X2022.08.09 = c(0, 0, 0, 0, 0, 0), X2022.08.10 = c(0,
0, 0, 0, 0, 0), X2022.08.11 = c(0, 0, 0, 0, 0, 0), X2022.08.12 = c(0,
0, 0, 0, 0, 0), X2022.08.15 = c(0, 0, 0, 0, 0, 0), X2022.08.16 = c(0,
0, 0, 0, 0, 0), X2022.08.17 = c(0, 0, 0, 0, 0, 0), X2022.08.18 = c(0,
0, 0, 0, 0, 0), X2022.08.19 = c(0, 0, 0, 0, 0, 0), X2022.08.22 = c(0,
0, 0, 0, 0, 0), X2022.08.23 = c(0, 0, 0, 0, 0, 0), X2022.08.24 = c(0,
0, 0, 0, 0, 0), X2022.08.25 = c(0, 0, 0, 0, 0, 0), X2022.08.26 = c(0,
0, 0, 0, 0, 0), X2022.08.29 = c(0, 0, 0, 0, 0, 0), X2022.08.30 = c(0,
0, 0, 0, 0, 0), X2022.08.31 = c(0, 0, 0, 0, 0, 0)), row.names = c(NA,
6L), class = "data.frame")
test_2 = structure(list(rn = c("Blue", "Pink",
"Red", "Yellow", "Green", "Gold"
), X2022.08.01 = c(10, 10, 10, 10, 10, 10), X2022.08.03 = c(10, 10, 10,
10, 10, 10), X2022.08.04 = c(10, 10, 10, 10, 10, 10), X2022.08.05 = c(10,
10, 10, 10, 10, 10), X2022.08.26 = c(10, 10, 10, 10, 10, 10)), row.names = c(NA,
6L), class = "data.frame")
所需的输出如下所示:
test_output = structure(list(rn = c("Red", "Blue",
"Green", "Yellow", "Pink", "Gold"
), X2022.08.01 = c(10, 10, 10, 10, 10, 10), X2022.08.02 = c(0, 0, 0,
0, 0, 0), X2022.08.03 = c(10, 10, 10, 10, 10, 10), X2022.08.04 = c(10,
10, 10, 10, 10, 10), X2022.08.05 = c(10, 10, 10, 10, 10, 10), X2022.08.08 = c(0,
0, 0, 0, 0, 0), X2022.08.09 = c(0, 0, 0, 0, 0, 0), X2022.08.10 = c(0,
0, 0, 0, 0, 0), X2022.08.11 = c(0, 0, 0, 0, 0, 0), X2022.08.12 = c(0,
0, 0, 0, 0, 0), X2022.08.15 = c(0, 0, 0, 0, 0, 0), X2022.08.16 = c(0,
0, 0, 0, 0, 0), X2022.08.17 = c(0, 0, 0, 0, 0, 0), X2022.08.18 = c(0,
0, 0, 0, 0, 0), X2022.08.19 = c(0, 0, 0, 0, 0, 0), X2022.08.22 = c(0,
0, 0, 0, 0, 0), X2022.08.23 = c(0, 0, 0, 0, 0, 0), X2022.08.24 = c(0,
0, 0, 0, 0, 0), X2022.08.25 = c(0, 0, 0, 0, 0, 0), X2022.08.26 = c(10,
10, 10, 10, 10, 10), X2022.08.29 = c(0, 0, 0, 0, 0, 0), X2022.08.30 = c(0,
0, 0, 0, 0, 0), X2022.08.31 = c(0, 0, 0, 0, 0, 0)), row.names = c(NA,
6L), class = "data.frame")
最佳答案
如果您使用源的列名作为赋值两侧的索引，则可以替换为
test_1[ ,colnames(test_2)] <- test_2[ , colnames(test_2)]
test_1
rn X2022.08.01 X2022.08.02 X2022.08.03 X2022.08.04 X2022.08.05 X2022.08.08 X2022.08.09
1 Blue 10 0 10 10 10 0 0
2 Pink 10 0 10 10 10 0 0
3 Red 10 0 10 10 10 0 0
4 Yellow 10 0 10 10 10 0 0
5 Green 10 0 10 10 10 0 0
6 Gold 10 0 10 10 10 0 0
X2022.08.10 X2022.08.11 X2022.08.12 X2022.08.15 X2022.08.16 X2022.08.17 X2022.08.18 X2022.08.19
1 0 0 0 0 0 0 0 0
2 0 0 0 0 0 0 0 0
3 0 0 0 0 0 0 0 0
4 0 0 0 0 0 0 0 0
5 0 0 0 0 0 0 0 0
6 0 0 0 0 0 0 0 0
X2022.08.22 X2022.08.23 X2022.08.24 X2022.08.25 X2022.08.26 X2022.08.29 X2022.08.30 X2022.08.31
1 0 0 0 0 10 0 0 0
2 0 0 0 0 10 0 0 0
3 0 0 0 0 10 0 0 0
4 0 0 0 0 10 0 0 0
5 0 0 0 0 10 0 0 0
6 0 0 0 0 10 0 0 0
我怀疑是否存在更简单的方法。只要索引位于目标矩阵或数据帧的列名和行名的正确子集，它甚至可以使用更有限的行数。注意:我不明白 NA 的问题。两种结构中都没有 NA。
关于r - R 中的合并表，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/74175715/