json - 如何使用jolt将嵌套数据变成线性数据

Question

如何使用 jolt 将这个嵌套数据转换为线性格式数据，如下所述。需要为所有嵌套数据创建单独的条目。每条记录应该有5个数据practice_loc,prac_num,topId,S1和S2。 需要为所有嵌套数据创建单独的条目。每条记录应该有5个数据practice_loc,prac_num,topId,S1和S2。 输入数据

[
 {
    "practice_loc": 120,
    "prac_num": 234,
    "topId": "t1",
    "subList": [
      {
        "S1": "A1",
        "S2": "B1"
      },
      {
        "S1": "A2"
      }
    ]
  },
 {
    "practice_loc": 334,
    "prac_num": 233,
    "topId": "plumcherry",
    "subList": [
      {
        "S1": "A3"
      }
    ]
  },
{
    "practice_loc": 987,
    "prac_num": 232,
    "topId": "artica",
    "subList": [
      {
        "S1": "A5",
        "S2": "B7"
      }
    ]
  },
{
    "practice_loc": 987,
    "prac_num": 232,
    "topId": "rose",
    "subList": [
      {
      }
    ]
  }
]

预期输出

[
{
    "practice_loc": 120,
    "prac_num": 234,
    "topId": "t1",
    "S1": "A1",
    "S2": "B1"
  },
  {
    "practice_loc": 120,
    "prac_num": 234,
    "topId": "t1",
    "S1": "A2",
    "S2":""
 },
{
    "practice_loc": 334,
    "prac_num": 233,
    "topId": "plumcherry",
    "S1": "A3",
    "S2":""    
},
{
    "practice_loc": 987,
    "prac_num": 232,
    "topId": "artica",
    "S1": "A5",
    "S2": "B7"
  },
{
"practice_loc": 987,
    "prac_num": 232,
    "topId": "rose",
     "S1": "",
    "S2":""
}
]

Answer 1

您可以将结果动态地呈现为

[
  { // group elements by upper level objects wrapper nodes
    "operation": "shift",
    "spec": {
      "*": {
        "subList": {
          "*": {
            "@2|@": "&3_&1"
          }
        }
      }
    }
  },
  { // get rid of the wrappers
    "operation": "shift",
    "spec": {
      "*": {
        "*": {
          "*": "[#3].&"
        }
      }
    }
  },
  { // get rid of the extra generated array, namely "subList"
    "operation": "remove",
    "spec": {
      "*": {
        "subList": ""
      }
    }
  }
]