我正在开发的 Laravel 应用程序有两个资源。
第二个资源的路由如下:
$ php artisan route:list | grep -i activity
POST | admin/procedure/{id}/activity | admin.procedure.{id}.activity.store | (...)\ProcedureActivityController@store
GET|HEAD | admin/procedure/{id}/activity | admin.procedure.{id}.activity.index | (...)\ProcedureActivityController@index
GET|HEAD | admin/procedure/{id}/activity/create | admin.procedure.{id}.activity.create | (...)\ProcedureActivityController@create
GET|HEAD | admin/procedure/{id}/activity/{activity} | admin.procedure.{id}.activity.show | (...)\ProcedureActivityController@show
PUT|PATCH | admin/procedure/{id}/activity/{activity} | admin.procedure.{id}.activity.update | (...)\ProcedureActivityController@update
DELETE | admin/procedure/{id}/activity/{activity} | admin.procedure.{id}.activity.destroy | (...)\ProcedureActivityController@destroy
GET|HEAD | admin/procedure/{id}/activity/{activity}/edit | admin.procedure.{id}.activity.edit | (...)\ProcedureActivityController@edit
我将此设置称为嵌套资源,因为事件是在过程下定义的。定义或路线如下所示:
Route::resource('procedure', 'ProcedureController');
Route::resource('procedure/{id}/activity', 'Admin\ProcedureActivityController');
我想为属于过程 3 的新事件生成 POST 操作的链接,就像使用 list-all-procedures 路由一样;
$ php artisan tinker
>>> route('admin.procedure.index')
=> "http://localhost/admin/procedure"
>>> route('admin.procedure.{id}.activity')
InvalidArgumentException with message
'Route [admin.procedure.{id}.activity] not defined.'
有没有办法使用标准助手和外观生成嵌套资源的链接?
最佳答案
您的嵌套资源的路由定义不太正确。
Route::resource('procedure/{id}/activity', 'Admin\ProcedureActivityController');
应该是:
Route::resource('procedure.activity', 'Admin\ProcedureActivityController');
此外,我不确定您如何在 URI 中获取 {id}
,因为 ResourceRegistrar 将根据资源名称创建参数。基于您的第一个资源定义应为 {procedure}
的定义。
您最终应该为索引路由提供一个类似于 admin.procedure.activity.index
的路由名称。
route('admin.procedure.activity.index', ['procedure' => $id]);
Laravel 5.1 - Controllers - Restful - Nested Resources
Route::resource('photos.comments', 'PhotoCommentController');
This route will register a "nested" resource that may be accessed with URLs like the following:
photos/{photos}/comments/{comments}
.
关于php - 如何生成嵌套资源的链接?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37343590/