如果类的所有对象的虚函数表都是相同的,那么为什么指向该表的指针 (vfptr) 不能是静态的并在所有对象之间共享?
最佳答案
vtable 本质上是静态的。但是您需要一个实际位于对象内部的 vptr 成员来执行虚拟分派(dispatch)和其他 RTTI 操作。
在 vptr 实现上,此 C++ 代码:
class Base {
public:
virtual void f();
};
class Derived : public Base {
public:
virtual void f();
};
可能会像下面这样:
class Base {
public:
Base::Base() : m_vptr(&Base_vtab) {}
Base::Base(const Base& b) : m_vptr(&Base_vtab) {}
void f() { (m_vptr->f_impl)(this); }
protected:
struct VTable {
void (*f_impl)(Base* self);
};
const VTable* m_vptr;
static const VTable Base_vtab;
private:
static void Base_f(Base* self);
};
const Base::VTable Base::Base_vtab = { &Base::Base_f };
class Derived : public Base {
public:
Derived::Derived() : Base() { m_vtpr = &Derived_vtab; }
Derived::Derived(const Derived& d) : Base(d) { m_vptr = &Derived_vtab; }
Derived::~Derived() { m_vptr = &Base::Base_vtab; }
protected:
static const VTable Derived_vtab;
private:
static void Derived_f(Derived* self);
static void Derived_f(Base* self) { Derived_f(static_cast<Derived*>(self)); }
};
const Base::VTable Derived::Derived_vtab = { &Derived::Derived_f };
关于c++ - 为什么在 C++ 中虚拟函数表指针 (vfptr) 不能是静态的?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25463790/