我是第一次尝试使用 rpy2。假设我在 python 中有一个列表
l = [1,2,3,4,5,6]
我想在 R 中调用
ks.test(l, pexp)
我怎样才能做到这一点？
我最初的尝试是
#!/usr/bin/python
import rpy2.robjects as robjects
l = [1,2,3,4,5]
f = robjects.r('''
f<-function(l){
ks.test(l, pexp)
}''')
print f(l)
据我所知，这显然不是正确的方法
Error in sort.int(x, na.last = na.last, decreasing = decreasing, ...) :
'x' must be atomic
Traceback (most recent call last):
File "./rpy2-test.py", line 12, in <module>
print f(l)
File "/usr/local/lib/python2.7/dist-packages/rpy2/robjects/functions.py", line 166, in __call__
return super(SignatureTranslatedFunction, self).__call__(*args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/rpy2/robjects/functions.py", line 99, in __call__
res = super(Function, self).__call__(*new_args, **new_kwargs)
rpy2.rinterface.RRuntimeError: Error in sort.int(x, na.last = na.last, decreasing = decreasing, ...) :
'x' must be atomic
执行此操作的正确方法是什么？
最佳答案
我认为你不能直接将 python 列表传递给 R。您可以在使用之前将其转换为 R int 向量。
#!/usr/bin/python
import rpy2.robjects as robjects
l = [1,2,3,4,5]
# get ks.test via execute string as R statement
test = robjects.r('ks.test')
# get a built-in functions variables directly
pexp = robjects.r.pexp
l_vector = robjects.IntVector(l)
result = test(l_vector, pexp)
print result[result.names.index('p.value')]
引用:
关于python - 如何在 rpy2 中将列表传递给 R 并返回结果，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/25269655/