javascript - 如何在多个条件下使用 .includes()？

Question

我正在使用 React Redux 构建 Yahtzee。在我的 scores reducer 中，我正在计算是否根据骰子状态为小直线奖励 30 分。骰子状态表示为一个数组，所以我必须检测这个数组是否包含 1、2、3、4 ... 2、3、4、5 ... 或 3、4、5、6。什么我想出了作品，但它看起来很乱(下图)。是否有更简洁的方法来检查这些值集是否出现在数组中？

    setSmallStraight: (state, action) => {
        if (
            action.payload.includes(1)
            && action.payload.includes(2)
            && action.payload.includes(3)
            && action.payload.includes(4)
            ||
            action.payload.includes(2)
            && action.payload.includes(3)
            && action.payload.includes(4)
            && action.payload.includes(5)
            ||
            action.payload.includes(3)
            && action.payload.includes(4)
            && action.payload.includes(5)
            && action.payload.includes(6)
        ) {
            state['Small Straight'] = 30
        } else {state['Small Straight'] = 0} 
    },

Answer 1

您可以使用 array.some() 和 array.every()

const small_straights = [
    [1, 2, 3, 4],
    [2, 3, 4, 5],
    [3, 4, 5, 6]
];

if (small_straights.some(dice => dice.every(die => action.payload.includes(die))) {
    state['Small Straight'] = 30;
} else {
    state['Small Straight'] = 0;
}