我想根据值从高到小用色标按值对列进行着色
像这样
目前,我在一个函数中创建了破折号表,并为每一列循环发送它;
def make_table_in_div(df, column_name):
pv = pd.pivot_table(df, index=[column_name], values=['val1'], aggfunc=['mean', 'count']).reset_index()
pv.columns = [column_name, 'val1', 'count']
print(column_name)
div = html.Div([html.H1(column_name), dash_table.DataTable(
columns=[{"name": i, "id": i} for i in pv.columns],
data=pv.to_dict('records'),
)], style={'height': 30, 'margin-right': 'auto', 'margin-left': 'auto', 'width': '800px'}) # 'width': '50%',
return div
div = [make_table_in_div(df, column_name) for column_name in ['column_name']]
return div
破折号表看起来像流动的图片,我想给值列着色最佳答案
感谢 The answer of Kristian Haga . - 效果很好。
我想为将来有同样问题的用户和我总结一下选项。当我们想在多列上运行它时,有两种选择:
discrete_background_color_bins(df, columns=['value','count'])
def discrete_background_color_bins(df, n_bins=7, columns='all'):
bounds = [i * (1.0 / n_bins) for i in range(n_bins+1)]
if columns == 'all':
if 'id' in df:
df_numeric_columns = df.select_dtypes('number').drop(['id'], axis=1)
else:
df_numeric_columns = df.select_dtypes('number')
else:
df_numeric_columns = df[columns]
df_max = df_numeric_columns.max().max()
df_min = df_numeric_columns.min().min()
ranges = [
((df_max - df_min) * i) + df_min
for i in bounds
]
styles = []
legend = []
for i in range(1, len(bounds)):
min_bound = ranges[i - 1]
max_bound = ranges[i]
backgroundColor = colorlover.scales[str(n_bins+4)]['div']['RdYlGn'][2:-2][i - 1]
color = 'black'
for column in df_numeric_columns:
styles.append({
'if': {
'filter_query': (
'{{{column}}} >= {min_bound}' +
(' && {{{column}}} < {max_bound}' if (i < len(bounds) - 1) else '')
).format(column=column, min_bound=min_bound, max_bound=max_bound),
'column_id': column
},
'backgroundColor': backgroundColor,
'color': color
})
legend.append(
html.Div(style={'display': 'inline-block', 'width': '60px'}, children=[
html.Div(
style={
'backgroundColor': backgroundColor,
'borderLeft': '1px rgb(50, 50, 50) solid',
'height': '10px'
}
),
html.Small(round(min_bound, 2), style={'paddingLeft': '2px'})
])
)
return (styles, html.Div(legend, style={'padding': '5px 0 5px 0'}))
我们将使用下面的函数:
(非常相似,但首先在列上运行)
def discrete_background_color_bins(df, n_bins=7, columns='all'):
bounds = [i * (1.0 / n_bins) for i in range(n_bins+1)]
if columns == 'all':
if 'id' in df:
df_numeric_columns = df.select_dtypes('number').drop(['id'], axis=1)
else:
df_numeric_columns = df.select_dtypes('number')
else:
df_numeric_columns = df[columns]
df_max = df_numeric_columns.max().max()
df_min = df_numeric_columns.min().min()
ranges = [
((df_max - df_min) * i) + df_min
for i in bounds
]
styles = []
legend = []
for i in range(1, len(bounds)):
min_bound = ranges[i - 1]
max_bound = ranges[i]
backgroundColor = colorlover.scales[str(n_bins+4)]['div']['RdYlGn'][2:-2][i - 1]
color = 'black'
for column in df_numeric_columns:
styles.append({
'if': {
'filter_query': (
'{{{column}}} >= {min_bound}' +
(' && {{{column}}} < {max_bound}' if (i < len(bounds) - 1) else '')
).format(column=column, min_bound=min_bound, max_bound=max_bound),
'column_id': column
},
'backgroundColor': backgroundColor,
'color': color
})
legend.append(
html.Div(style={'display': 'inline-block', 'width': '60px'}, children=[
html.Div(
style={
'backgroundColor': backgroundColor,
'borderLeft': '1px rgb(50, 50, 50) solid',
'height': '10px'
}
),
html.Small(round(min_bound, 2), style={'paddingLeft': '2px'})
])
)
return (styles, html.Div(legend, style={'padding': '5px 0 5px 0'}))
关于python-3.x - python破折号表条件格式色标,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/63372283/