python - 捕获特定范围时出错

Question

你好python社区，
如何阻止此循环？

error33 = int(2)
    while error33 > 1:
        while True:
                try:
                    survivalrateforjuveniles = float(input("Please enter the survival rate for poomen"))##Float input is being used as
                    break
                except ValueError:
                    print("Please enter a number between 0 and 1")
                    continue
                else:
                    break

非常感谢

Answer 1

这有效...

error33 = 2
while error33 > 1:
        while True:
                try:
                    survivalrateforjuveniles = float(input("Please enter the survival rate for poomen\n"))
                    break
                except ValueError:
                    print("Please enter a number between 0 and 1")
                    continue
                else:
                    error33 = 0
                    break

我不知道您在做什么...但是我想我会使用类似以下内容:

error33 = 2
survivalrateforjuveniles = -1.0
while error33 > 1:
    while not (0 < survivalrateforjuveniles < 1):
        survivalrateforjuveniles = input("Please enter the survival rate for poomen\n")
        try:
            survivalrateforjuveniles = float(survivalrateforjuveniles)
        except ValueError:
            survivalrateforjuveniles = -1
        print("Please enter a number between 0 and 1")

    print('do what you want')
    error33 =0

与您的解决方案没有太大不同，但是您不需要break并且看起来更健壮。但是，创建一个函数来读取survivalrate...和其他输入(我想您已经拥有)会更好，因为您不会多次使用同一行代码(这是编写优秀软件的基本实践之一) 。