python - 在我得到特定范围内的整数之前，如何继续要求用户输入？

Question

我最近决定重新审视我的TicTacToe游戏，该游戏是我大约3个月前制作的，需要重新调试，并且有一个特别的bug一直困扰着我。基本上，我有以下代码:

def player_choice(board):
    '''Asks the player for their next position, calls a func to check if it's free'''
    '''and returns the position if it's free for later use'''
    spot = None
    while spot not in range(1, 10) or not space_check(board, spot):
        try:
            spot = int(input("Choose your next position (1-9): "))
        except:
            print("Hmm, looks to me like your input was invalid")
        else:
            break
    return spot

这是一个更大的方案中的函数，但使整个游戏中断的是我需要一个整数作为输入，严格来说，范围在1到10之间。在尝试错误处理之前，我使用了while循环，该循环不断询问是否提供了str:

spot = int(input("Choose your next position (1-9): "))
    while spot not in range (1, 10) or not space_check(board, spot):
        spot = int(input("Looks like the spot you're trying to choose is invalid!\nPlease choose another position (1-9): "))
    return spot

但是后来我切换到了这个版本，这里它不会接受str作为输入，但是会接受1-10范围之外的int值。我的问题是:我该怎么做才能按照我需要的方式工作，取一个严格介于1到10之间的整数并继续询问直到精确提供此输入？

Answer 1

四处移动，这似乎可行。虽然我不知道为什么else总是被触发...

def player_choice2(board):
    '''Asks the player for their next position, calls a func to check if it's free'''
    '''and returns the position if it's free for later use'''
    try:
        spot = int(input("Choose your next position (1-9): "))
    except:
        print("Hmm, looks to me like your input was invalid")
        spot = 0
    while spot not in range(1, 10) or not space_check(board, spot):
        try:
            spot = int(input("Choose your next position **  (1-9) **: "))
        except:
            print("Hmm, looks to me like your input was invalid")
        else:
            # This always fires...?
            print("Else....")
    return spot