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已关闭8年。
我正在Haskell中编写Brainf * ck口译员。
我正在尝试打印
(chr (fromEnum $ getMem state))，这只是Word8到Char的转换。
然后我想在特定情况下打印后返回新状态
'.' -> do hPutChar stdout (chr (fromEnum $ getMem state))
hFlush stdout
return state { prog_pointer = prog_pointer state}
我收到此错误消息
The function `hPutChar' is applied to six arguments,
but its type `Handle -> Char -> IO ()' has only two
In a stmt of a 'do' block:
hPutChar
stdout
(chr (fromEnum $ getMem state))
hFlush
stdout
return
(state {prog_pointer = prog_pointer state})
用这个代码
iterateBF :: BFState -> IO BFState
iterateBF state = case (program state !! prog_pointer state) of
--some more cases here--
'.' -> do hPutChar stdout (chr (fromEnum $ getMem state))
hFlush stdout
return state { prog_pointer = prog_pointer state}
我似乎无法弄清楚为什么我会收到此错误。
经过左转和sabauma的评论后，我将代码编辑为
iterateBF :: BFState -> IO BFState
iterateBF state = case (program state !! prog_pointer state) of
--some more cases here--
'.' -> do hPutChar stdout (chr (fromEnum $ getMem state))
hFlush stdout
return state { prog_pointer = prog_pointer state}
这次仅使用空格。
但是，我得到
parse error on input 'hFlush'有人知道为什么吗？