ios - 如何比较数组与嵌套数组并打印匹配对，而不是匹配的值列表？ (代码有助于说明)

Question

我不确定如何将它写成文字，但是代码应该会有所帮助。

var People = [

      .init(name: "Sam", friends: ["James", "Tom", "Rick"]),
      .init(name: "Tom", friends: ["Callum", "Steve", "Sam"]),
      .init(name: "Adam", friends: ["Harry", "Diane", "William"]),
      .init(name: "William", friends: ["Rodger", "Adam", "Bill"]),
      .init(name: "Guy", friends: ["Zack", "Frank", "Cody"])
]

我想生成一个打印警报

" Sam is in the same social circle as Tom " / " Tom is in the same social circle as Sam "

和

" Adam is in the same social circle as William " / " William is in the same social circle as Adam "

和

" Guy has no common social circles "

我尝试过的方法是先创建一个名称数组:[String]，然后对 friend 做同样的事情，使用以下函数将[[String]]转换为[String] ...

func loadNamesArray() -> [String] {
    return self.People.map { $0.name }
}

func loadFriendsArray() -> [String] {
    let arrayOfFriends = self.People.map { $0.friends }
    let friends = arrayOfFriends.flatMap { $0 }
    return friends
}

然后，我交叉比较了两个数组，以警告使用此功能的任何普通人...

func loadCommonInteractingArray() -> [String] {
    let output = loadNamesArray().filter{ loadFriendsArray().contains($0) }

    return output
}

但这只会返回[“Sam”，“Tom”，“Adam”，“William”]，而且我不确定从哪里可以得到想要的结果，即识别匹配对，而不只是列表那些匹配。

谢谢

Answer 1

struct Person {
    let name: String
    let friends: [String]
}

var people: [Person] = [
      .init(name: "Sam", friends: ["James", "Tom", "Rick"]),
      .init(name: "Tom", friends: ["Callum", "Steve", "Sam"]),
      .init(name: "Adam", friends: ["Harry", "Diane", "William"]),
      .init(name: "William", friends: ["Rodger", "Adam", "Bill"])]

func loadCommonInteracting(in people: [Person]) -> [String] {
    var connections: [String] = []
    people.forEach { person in
        let friends = people.filter{ $0.friends.contains(person.name) }
        for friend in friends {
            connections.append("\(person.name) is in the same social circle as \(friend.name)")
        }
        
    }
    return connections
}

let connections = loadCommonInteracting(in: people)
for connection in connections {
    print(connection)
}

这将打印

山姆和汤姆在同一个社交圈
汤姆和山姆在同一个社交圈
亚当与威廉处于同一个社交圈
威廉与亚当处于同一个社交圈