ios - 要知道哪个 UILongPressGestureRecognizer 被触发

Question

我加 UILongPressGestureRecognizer给几个 UIButton使用代码:

UILongPressGestureRecognizer *longPress = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(btnLong:)];
[btnOne addGestureRecognizer:longPress]; //there are btnTwo, btnThree for example

当我长按一个按钮时，该方法被调用:

-(void)btnLong:(UILongPressGestureRecognizer *)gestureRecognizer{

    if ([gestureRecognizer state] == UIGestureRecognizerStateBegan) {
    }
}  

我的问题是，我怎么知道是哪个 UILongPressGestureRecognizer被触发，因为 UILongPressGestureRecognizer 没有标签属性.

Answer 1

给每个按钮一个唯一的标签号。然后在您的操作方法中，您可以执行以下操作:

-(void)btnLong:(UILongPressGestureRecognizer *)gestureRecognizer{
    if ([gestureRecognizer state] == UIGestureRecognizerStateBegan) {
        UIView *view = gestureRecognizer.view;
        if (view.tag == 1) { // first button's tag
            // process 1st button
        } else if (view.tag == 2) { // second button's tag
            // process 2nd button
        }
    }
}

另一种选择，如果每个按钮都有 socket ，您可以执行以下操作:

-(void)btnLong:(UILongPressGestureRecognizer *)gestureRecognizer{
    if ([gestureRecognizer state] == UIGestureRecognizerStateBegan) {
        UIView *view = gestureRecognizer.view;
        if (view == self.firstButton) {
            // process 1st button
        } else if (view == self.secondButton) {
            // process 2nd button
        }
    }
}

在哪里 firstButton和 secondButton是您的按钮属性。是的，使用 ==适合检查手势的 View 是否是按钮之一，因为您确实是要比较对象指针。