ios - ios 5 中带有 Storyboard 的 Table ViewController

Question

我已经开始使用 Storyboard，这是 iOS 5 中的一个新功能，所以我从一个选项卡式应用程序开始，然后我添加了一个表格 View Controller 并用一些虚拟数据填充单元格，现在，表格有 4 个单元格，现在点击每个单元格，我想打开一个新的ViewController，每个单元格都不同，

所以以前，我曾经这样编码

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
   [tableView deselectRowAtIndexPath:indexPath animated:YES];

    if(indexPath.row == 0)
    {
        FirstViewController *settingsView =[[FirstViewController alloc]initWithNibName:@"FirstViewController" bundle:nil];
        [self.navigationController pushViewController:settingsView animated:YES]; 
    }
 if(indexPath.row == 1)
    {
        SecondViewController *settingsView =[[SecondViewController alloc]initWithNibName:@"SecondViewController" bundle:nil];
        [self.navigationController pushViewController:settingsView animated:YES]; 
    }
 if(indexPath.row == 2)
    {
        ThirdViewController *settingsView =[[ThirdViewController alloc]initWithNibName:@"ThirdViewController" bundle:nil];
        [self.navigationController pushViewController:settingsView animated:YES]; 
    }

}

但是知道，我该怎么做..请帮帮我

感谢和问候
兰 git

Answer 1

也许本教程会对您有所帮助？
http://kurrytran.blogspot.com/2011/10/ios-5-storyboard-uitableview-tutorial.html

正如我所看到的 (performSegueWithIdentifier:sender:) 应该是从 Storyboard 执行新 View Controller 的方法

https://developer.apple.com/library/ios/#documentation/UIKit/Reference/UIViewController_Class/Reference/Reference.html#//apple_ref/occ/instm/UIViewController/performSegueWithIdentifier:sender :