代码示例:
struct A {};
struct B { using A = A; };
int main()
{
B b;
}
Clang 编译它。但是 GCC 给出了以下错误 ( demo ):
declaration of 'using A = struct A' changes meaning of 'A'
If a class name ([class.name]) or enumeration name ([dcl.enum]) and a variable, data member, function, or enumerator are declared in the same declarative region (in any order) with the same name (excluding declarations made visible via using-directives ([basic.lookup.unqual])), the class or enumeration name is hidden wherever the variable, data member, function, or enumerator name is visible.
UPD.0:感谢来自莫斯科的 Vlad
A name N used in a class S shall refer to the same declaration in its context and when re-evaluated in the completed scope of S. No diagnostic is required for a violation of this rule
这是否意味着 GCC 行为不正确?谢谢!
最佳答案
看来是gcc的bug。根据 C++ 20 标准(6.3.7 类作用域)
2 A name N used in a class S shall refer to the same declaration in its context and when re-evaluated in the completed scope of S. No diagnostic is required for a violation of this rule.
在这种情况下
struct A {};
struct B { using A = A; };
名称 B::A
指的是 struct A
的相同声明。
这是 C++ 标准中的一个示例,它显示了引号的含义。
typedef char* T;
struct Y {
T a; // error: T refers to ::T but when reevaluated is Y::T
typedef long T;
T b;
};
关于c++ - 使用 'using' 指令隐藏名字,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61455507/