我正在使用 laravel 4.2,目前我不知道如何使用 AJAX 将 csv 文件保存到 public\csv\
目录中。我仍在寻找一些答案。也许有人可以帮我解决这个问题。
这是我的代码:
在 Blade View 中:
{{Form::open(['route' => 'file_upload', 'files' => true, 'id' => 'upload_form', 'method' => 'POST'])}}
{{Form::file('csv_upload', ['id' => 'uploaded_file', 'accept' => 'text/csv'])}}
{{Form::submit('submit', ['class' => 'btn btn-primary btn-xs', 'id' => 'upload'])}}
{{Form::close()}}
Javascript Ajax:
var ajax_ready = 1
var token = {{Session::get('_token')}}
if($.type(originalOptions.data) === 'string') {
options.data = originalOptions.data+"&_token="+token;
}else if($.type(originalOptions.data) === 'object') {
//Here I got a new error
}else{
options.data = $.param(($.extend(originalOptions.data, {'_token':mmad_token})));
}
options.url = originalOptions.url.slice(0,originalOptions.url.indexOf("?_token="));
if (ajax_ready!=1){
jqXHR.abort();
}
ajax_ready = 0;
});
$('form#upload_form').on('submit', function(e){
e.preventDefault();
var uploadFile = $('#uploaded_file');
var ext = $("input#uploaded_file").val().split(".").pop().toLowerCase();
var file = $('input[name="csv_upload"]').val();
if($.inArray(ext, ["csv"]) === -1) {
alert("Please upload a .csv file!");
return false;
}
var csv = uploadFile[0].files;
var form = new FormData(this);
var csvFile = {lastModifed: csv[0].lastModified, fileName: csv[0].name, size: csv[0].size, fileType: csv[0].type};
$.post('{{ URL::route("file_upload") }}?_token={{Session::token()}}',{
data: form
}).done(function(response){
});
});
PHP:
public function upload_csv()
{
$inputs = Input::all();
$csvFile = $inputs['data']['fileName'];
$path = public_path().DIRECTORY_SEPARATOR.'csv'.DIRECTORY_SEPARATOR;
$path2 = public_path('csv/');
if(is_dir($path2))
{
@move_uploaded_file($csvFile, $path2.$csvFile); //This line can't move the uploaded files in my desired directory
}
return json_encode(['success' => 1, 'description' => 'Successfully Upload File']);
}
以下代码在不使用 AJAX 时也能正常工作:
if(Input::hasFile('csv_upload'))
{
$file = Input::file('csv_upload');
$originalFilename = $file->getClientOriginalName();
$rules = ['csv_upload' => 'required|file:csv'];
$validate = Validator::make(['csv_upload' => $file], $rules);
if($validate->fails())
{
return json_encode(['error' => 1, 'description' => 'File must be in .csv format']);
}
$path = public_path('/csv/');
if(!file_exists($path))
{
mkdir($path);
}
}
csv的控制台日志
最佳答案
您不能移动文件,因为当您使用 ajax 提交表单时 file is not being sent with ajax,For sending file you have to send file with FormData() javascript对象。
如果您通过放置 print_r($_FILES);
checkin upload_csv
Controller ,您将得到空数组。
所以使用FormData在客户端附加文件,然后尝试 agian。
你没有得到错误,因为你使用了 php 错误控制运算符 喜欢@move_uploaded_file($csvFile, $path2.$csvFile);
。
如果您需要工作示例,请告诉我,我会给您。
帮助代码: 1. 在 Blade View 中:
<script type="text/javascript">
$('form#upload_form').on('submit', function(e){
e.preventDefault();
var uploadFile = $('#uploaded_file');
var ext = $("input#uploaded_file").val().split(".").pop().toLowerCase();
var file = $('input[name="mmad_csv_upload"]').val();
if($.inArray(ext, ["csv"]) === -1) {
alert("Please upload a .csv file!");
return false;
}
var csv = uploadFile[0].files;
var formData = new FormData($(this)[0]);
formData.append('uploaded_file', $("#uploaded_file")[0].files[0]);
formData.append('lastModifed', csv[0].lastModified);
formData.append('fileName', csv[0].name);
console.log(formData);
$.ajax({
url: '{{ URL::route("file_upload") }}',
type: 'POST',
data: formData,
async: true,
cache: false,
contentType: false,
processData: false,
success: function (returndata) { //alert(returndata); return false;
}
});
});
</script>
2. Controller
public function file_upload(Request $request)
{
$inputs = Input::all();
$csvFile = $inputs['fileName'];
$path = public_path().DIRECTORY_SEPARATOR.'csv'.DIRECTORY_SEPARATOR;
$path2 = public_path('/csv/');
if(is_dir($path2))
{
$success = $request->file('uploaded_file')->move($path2, $csvFile);
}
return json_encode(['success' => 1, 'description' => 'Successfully Upload File']);
}
关于php - 如何在 laravel 4.2 中使用带有自定义预过滤器的 AJAX 上传 CSV 文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33299545/