我有下表:
-----------------------------------------------------------
ID oDate oName oItem oQty oRemarks
-----------------------------------------------------------
1 2016-01-01 A 001 2
2 2016-01-01 A 002 1 test
3 2016-01-01 B 001 3
4 2016-01-02 B 001 2
5 2016-01-02 C 001 2
6 2016-01-03 B 002 1
7 2016-01-03 B 001 4
ff.
我想获取每个名称的最新记录。所以结果应该是这样的:-----------------------------------------------------------
oDate oName oItem oQty oRemarks
-----------------------------------------------------------
2016-01-01 A 001 2
2016-01-01 A 002 1 test
2016-01-02 C 001 2
2016-01-03 B 002 1
2016-01-03 B 001 4
ff.
有谁知道如何得到这个结果?
最佳答案
rank
window 子句允许您根据某些分区对行进行排名,然后您可以只选择顶部的行:
SELECT oDate, oName, oItem, oQty, oRemarks
FROM (SELECT oDate, oName, oItem, oQty, oRemarks,
RANK() OVER (PARTITION BY oName ORDER BY oDate DESC) AS rk
FROM my_table) t
WHERE rk = 1
关于sql - 获取每个 Group By SQL 的最新记录,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35219261/