我有一个文件名向量和一个包含每个文件名的“组”名称的数据框。
files <- c("data/backup/LATEST/20181514.X1235",
"data/backup/LATEST/X1255+20181514",
"data/backup/LATEST/20181514-X1237",
"data/backup/LATEST/20181514-E1235",
"data/backup/LATEST/20181514F1235",
"data/backup/LATEST/M32_-X6635__20181514",
"data/backup/LATEST/20181514-X1205",
"data/backup/LATEST/l-A1230.20181514-XX")
groups <- data.frame(
ID = c("X1235","X1255","A1230","K93430",
"LOP0343","J3490","X1205","X6635",
"F1235","E1235","X1237"),
Group = c("A","A","A",
"B","A","A",
"B","B","B",
"B","A")
)
作为最终结果,我想要一个包含来自
files
的完整文件路径的列的数据框和第二列显示其 group
.我怎样才能做到这一点?
结果
filepath group
1 data/backup/LATEST/20181514.X1235 A
2 data/backup/LATEST/X1255+20181514 A
3 data/backup/LATEST/20181514-X1237 A
4 data/backup/LATEST/20181514-E1235 B
5 data/backup/LATEST/20181514F1235 B
6 data/backup/LATEST/M32_-X6635__20181514 B
7 data/backup/LATEST/20181514-X1205 B
8 data/backup/LATEST/l-A1230.20181514-XX A
最佳答案
这是一种使用 stringr::str_detect
的方法
library(stringr)
strdet <- function(x){
#browser()
groups[str_detect(x,groups$ID),'Group']
}
apply(df, 1, strdet)
[1] "A" "A" "A" "B" "B" "B" "B" "A"
PS:stringAsFactor=FALSE
读取了 df数据
df <- data.frame(files, stringsAsFactors = FALSE)
关于如果两个向量之间存在 grep 匹配,则返回数据帧的不同列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52181444/