java - 蒙蒂霍尔游戏

Question

我是一名新程序员，目前正在学习 Java。我在这里有一个基于游戏让我们做个交易和 monty hall 问题 (https://www.youtube.com/watch?v=mhlc7peGlGg) 的游戏，我一直对这段代码的逻辑有疑问。一切似乎都正常，除了我似乎无法让 user_door 切换到另一扇门并正确确定他们是否是赢家。如果有人可以帮助我理解我在这里做错了什么，我很乐意借此机会学习，谢谢!

import java.util.Random;
import java.util.Scanner;
public class GameShow {

public static void main(String[] args) {
    Scanner scan = new Scanner (System.in);
    Random generator = new Random();

    // Initialize Variables
    int user_door,
        open_door,
        other_door,
        prize_door;

    // Generate random value 1-3
    prize_door = generator.nextInt(3)+1;
    open_door = prize_door;

    while(open_door == prize_door){
        open_door = generator.nextInt(3)+1;
    }

    other_door = open_door;

    while (other_door == open_door || other_door == prize_door){
        other_door = generator.nextInt(3)+1;
    }

    // Begin Game
    System.out.println("*** Welcome to the game show! ***");  
    System.out.println("Select the door (1, 2, or 3): ");
    user_door = scan.nextInt();


    // User Validation
        if (user_door > 3 || user_door < 0) {
            System.out.println("Please select door 1, 2, or 3");
            user_door = scan.nextInt();
        } else if(user_door == 1 || user_door == 2 ||  user_door == 3) {

    //Continue Game
    System.out.println("\nIn a moment, I will show you where the prize is located,");
    System.out.println("but first I will show you what is behind one of the other doors");

    //Continue Dialogue
    System.out.println("\nBehind door number " + open_door + " are goats!");
    System.out.println("You selected door number " + user_door);
    System.out.println("\nWould you like to switch your door(y/n)? ");

    //User Input Yes or No
    char userReply = scan.next().charAt(0);

    //If statement with nested while statements for user input
        if (userReply == 'y'){
                user_door = other_door;
                } while(userReply != 'y' && userReply != 'n')
                {
                    //User Validation
                    System.out.println("Please enter either y/n");
                    userReply = scan.next().charAt(0);
                } 

    System.out.println("The prize is behind door number: " + prize_door); 

    //Check to see if user won or lost
        if(user_door == prize_door){
            System.out.println("Congratulations! You won the prize!");
            } else {
                    System.out.println("Sorry. You lost.");
                    }       

        }
    }
}

Answer 1

我同意 Srikanth 上面所说的。缺少的是测试用户回复的部分。你应该切换“if”和“while”语句。这将有助于解决您的门开关问题。

之前

 if (userReply == 'y')
     {
     user_door = other_door;
     }  
 while(userReply != 'y' && userReply != 'n')
     {
     //User Validation
     System.out.println("Please enter either y/n");
     userReply = scan.next().charAt(0);
     } 

改为

 while(userReply != 'y' && userReply != 'n')
    {
        //User Validation
        System.out.println("Please enter either y/n");
        userReply = scan.next().charAt(0);
    }
 if (userReply == 'y')
    {
     user_door = other_door;
    } 

你这样做的方式只检查第一次输入一个字符。如果他们做错了并试图再做一次，那么它就不会切换门，因为你已经过了程序的那部分。