为什么
(<benefitStartDate>20170101</benefitStartDate>,<benefitEndDate>20170301</benefitEndDate>,
<benefitStartDate>20170101</benefitStartDate>,<benefitEndDate>20170501</benefitEndDate>)/distinct-values(.)
产量 20170101 20170301 20170101 20170501 (即不消除重复)
但将其应用于序列的原子化版本
distinct-values((20170701,20170301,20170701,20170501))产量20170701 20170301 20170501
最佳答案
(
<benefitStartDate>20170101</benefitStartDate>,<benefitEndDate>20170301</benefitEndDate>,
<benefitStartDate>20170101</benefitStartDate>,<benefitEndDate>20170501</benefitEndDate>
)/distinct-values(.)
不一样:
distinct-values(
<benefitStartDate>20170101</benefitStartDate>,<benefitEndDate>20170301</benefitEndDate>,
<benefitStartDate>20170101</benefitStartDate>,<benefitEndDate>20170501</benefitEndDate>
)
后者返回元素序列的不同值。
您的代码返回每个元素的不同值，就像调用:
(
distinct-values(<benefitStartDate>20170101</benefitStartDate>),
distinct-values(<benefitEndDate>20170301</benefitEndDate>),
distinct-values(<benefitStartDate>20170101</benefitStartDate>),
distinct-values(<benefitEndDate>20170501</benefitEndDate>)
)
返回您预期结果的另一个变体是:
(
<benefitStartDate>20170101</benefitStartDate>,<benefitEndDate>20170301</benefitEndDate>,
<benefitStartDate>20170101</benefitStartDate>,<benefitEndDate>20170501</benefitEndDate>
) => distinct-values()
最好的
迈克尔
关于xpath - 为什么不同值不会在非原子化序列上产生不同的值，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/45904288/