我有以下 XML 文档,由 Azure Logic Apps 从 EDI 856 解码:
<ins0:X12InterchangeXml DelimiterSetSerializedData="13:10:-1:42:60:-1:-1:-1:-1"
xmlns:ins0="http://schemas.microsoft.com/BizTalk/EDI/X12/2006/InterchangeXML">
<ns0:ISA
xmlns:ns0="http://schemas.microsoft.com/Edi/X12ServiceSchema">
<ISA01>00</ISA01>
<ISA02></ISA02>
<ISA03>01</ISA03>
<ISA04></ISA04>
<ISA05>ZZ</ISA05>
<ISA06>123456789 </ISA06>
<ISA07>12</ISA07>
<ISA08>9987654321 </ISA08>
<ISA09>180102</ISA09>
<ISA10>2108</ISA10>
<ISA11>U</ISA11>
<ISA12>00400</ISA12>
<ISA13>000000351</ISA13>
<ISA14>0</ISA14>
<ISA15>P</ISA15>
<ISA16><</ISA16>
</ns0:ISA>
<FunctionalGroup DocType="http://schemas.microsoft.com/BizTalk/EDI/X12/2006#X12_00401_856">
<ns0:GS
xmlns:ns0="http://schemas.microsoft.com/Edi/X12ServiceSchema">
<GS01>SH</GS01>
<GS02>123456789</GS02>
<GS03>9987654321</GS03>
<GS04>20180102</GS04>
<GS05>2108</GS05>
<GS06>351</GS06>
<GS07>X</GS07>
<GS08>004010</GS08>
</ns0:GS>
<TransactionSet DocType="http://schemas.microsoft.com/BizTalk/EDI/X12/2006#X12_00401_856">
<ns0:X12_00401_856
xmlns:ns0="http://schemas.microsoft.com/BizTalk/EDI/X12/2006">
<ST>
<ST01>856</ST01>
<ST02>000351</ST02>
</ST>
<ns0:BSN>
<BSN01>00</BSN01>
<BSN02>SID87447</BSN02>
<BSN03>20180102</BSN03>
<BSN04>2108</BSN04>
</ns0:BSN>
<ns0:DTM>
<DTM01>011</DTM01>
<DTM02>20180102</DTM02>
<DTM03>2109</DTM03>
<DTM04>ET</DTM04>
</ns0:DTM>
<ns0:HLLoop1>
<ns0:HL>
<HL01>1</HL01>
<HL03>S</HL03>
<HL04>1</HL04>
</ns0:HL>
<ns0:MEA>
<MEA01>PD</MEA01>
<MEA02>G</MEA02>
<MEA03>9985</MEA03>
<ns0:C001_2>
<C00101>LB</C00101>
</ns0:C001_2>
</ns0:MEA>
<ns0:MEA>
<MEA01>PD</MEA01>
<MEA02>N</MEA02>
<MEA03>9174</MEA03>
<ns0:C001_2>
<C00101>LB</C00101>
</ns0:C001_2>
</ns0:MEA>
<ns0:TD1>
<TD101>CTN90</TD101>
<TD102>55</TD102>
</ns0:TD1>
<ns0:TD5>
<TD501>B</TD501>
<TD502>2</TD502>
<TD503>LODQ</TD503>
<TD504>M</TD504>
</ns0:TD5>
<ns0:TD3>
<TD301>TL</TD301>
<TD303>1</TD303>
</ns0:TD3>
<ns0:REF>
<REF01>BM</REF01>
<REF02>SID87447</REF02>
</ns0:REF>
<ns0:N1Loop1>
<ns0:N1>
<N101>SU</N101>
<N103>92</N103>
<N104>8888</N104>
</ns0:N1>
</ns0:N1Loop1>
</ns0:HLLoop1>
<ns0:HLLoop1>
<ns0:HL>
<HL01>2</HL01>
<HL02>1</HL02>
<HL03>O</HL03>
<HL04>1</HL04>
</ns0:HL>
<ns0:PRF>
<PRF01>2018002A</PRF01>
</ns0:PRF>
<ns0:REF>
<REF01>MH</REF01>
<REF02>50945</REF02>
</ns0:REF>
<ns0:N1Loop1>
<ns0:N1>
<N101>SU</N101>
<N103>92</N103>
<N104>8888</N104>
</ns0:N1>
</ns0:N1Loop1>
</ns0:HLLoop1>
<ns0:HLLoop1>
<ns0:HL>
<HL01>3</HL01>
<HL02>2</HL02>
<HL03>I</HL03>
<HL04>0</HL04>
</ns0:HL>
<ns0:LIN>
<LIN02>BP</LIN02>
<LIN03>58706-02010-00V</LIN03>
<LIN04>RC</LIN04>
<LIN05>S0467</LIN05>
</ns0:LIN>
<ns0:SN1>
<SN102>1029</SN102>
<SN103>EA</SN103>
</ns0:SN1>
</ns0:HLLoop1>
<ns0:HLLoop1>
<ns0:HL>
<HL01>4</HL01>
<HL02>2</HL02>
<HL03>I</HL03>
<HL04>0</HL04>
</ns0:HL>
<ns0:LIN>
<LIN02>BP</LIN02>
<LIN03>61327-0R030-K0V</LIN03>
<LIN04>RC</LIN04>
<LIN05>B0058</LIN05>
</ns0:LIN>
<ns0:SN1>
<SN102>858</SN102>
<SN103>EA</SN103>
</ns0:SN1>
</ns0:HLLoop1>
<ns0:HLLoop1>
<ns0:HL>
<HL01>5</HL01>
<HL02>2</HL02>
<HL03>I</HL03>
<HL04>0</HL04>
</ns0:HL>
<ns0:LIN>
<LIN02>BP</LIN02>
<LIN03>61328-0R030-K0V</LIN03>
<LIN04>RC</LIN04>
<LIN05>B0059</LIN05>
</ns0:LIN>
<ns0:SN1>
<SN102>858</SN102>
<SN103>EA</SN103>
</ns0:SN1>
</ns0:HLLoop1>
<ns0:CTT>
<CTT01>5</CTT01>
</ns0:CTT>
<SE>
<SE01>26</SE01>
<SE02>000351</SE02>
</SE>
</ns0:X12_00401_856>
</TransactionSet>
<ns0:GE
xmlns:ns0="http://schemas.microsoft.com/Edi/X12ServiceSchema">
<GE01>1</GE01>
<GE02>351</GE02>
</ns0:GE>
</FunctionalGroup>
<ns0:IEA
xmlns:ns0="http://schemas.microsoft.com/Edi/X12ServiceSchema">
<IEA01>1</IEA01>
<IEA02>000000351</IEA02>
</ns0:IEA>
我试图编写一个 XSLT 来对其进行转换,此时我有:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ins0="http://schemas.microsoft.com/BizTalk/EDI/X12/2006/InterchangeXML"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
xmlns:ns0="http://schemas.microsoft.com/Edi/X12ServiceSchema">
<EDI_Message>
<Mailbox>
<Mailbox_Code>
<xsl:value-of select="normalize-space(/ins0:X12InterchangeXml/ns0:ISA/ISA06/text())" />
</Mailbox_Code>
<Mailbox_Qualifier>
<xsl:value-of select="/ins0:X12InterchangeXml/ns0:ISA/ISA05/text()" />
</Mailbox_Qualifier>
<Destination_Qualifier>
<xsl:value-of select="/ins0:X12InterchangeXml/ns0:ISA/ISA07/text()" />
</Destination_Qualifier>
<Destination_Mailbox>
<xsl:value-of select="normalize-space(/ins0:X12InterchangeXml/ns0:ISA/ISA08/text())"/>
</Destination_Mailbox>
<Destination_Code>
<xsl:value-of select="/ins0:X12InterchangeXml/FunctionalGroup/ns0:GS/GS03/text()" />
</Destination_Code>
<Origin_Code>
<xsl:value-of select="/ins0:X12InterchangeXml/FunctionalGroup/TransactionSet/ns0:X12_00401_856/ns0:HLLoop1/ns0:N1Loop1/ns0:N1/N104/text()" />
</Origin_Code>
<Vendor_Code>
<xsl:value-of select="/ins0:X12InterchangeXml/FunctionalGroup/ns0:GS/GS02/text()" />
</Vendor_Code>
<Supplier_Code />
<Actual_Processor_Duns />
<Transmission_Count>
<xsl:value-of select="normalize-space(/ins0:X12InterchangeXml/ns0:ISA/ISA13/text())"/>
</Transmission_Count>
<Ship_From_Code />
<Mailbox_Status>
<xsl:value-of select="normalize-space(/ins0:X12InterchangeXml/ns0:ISA/ISA15/text())"/>
</Mailbox_Status>
<Seller_Identification_Number />
<Element_Separator>*</Element_Separator>
<Subelement_Separator>
<xsl:value-of select="normalize-space(/ins0:X12InterchangeXml/ns0:ISA/ISA16/text())"/>
</Subelement_Separator>
<Segment_Terminator_ASCII_Code>126</Segment_Terminator_ASCII_Code>
<!--Character separating segments, I guess in this case it is the LF character-->
</Mailbox>
</EDI_Message>
</xsl:template>
由于 Azure 创建源文档。我不能真正改变它,或者它是如何使用命名空间声明的。我的问题是在这一点上:
<Origin_Code>
<xsl:value-of select="/ins0:X12InterchangeXml/FunctionalGroup/TransactionSet/ns0:X12_00401_856/ns0:HLLoop1/ns0:N1Loop1/ns0:N1/N104/text()" />
</Origin_Code>
我没有得到值(value)。要么我的 XPATH 错误,要么我与使用 ns0 两次的 Azure 文档发生冲突,一次为
<ns0:ISA
xmlns:ns0="http://schemas.microsoft.com/Edi/X12ServiceSchema">
然后在同一个文档中:
<ns0:X12_00401_856
xmlns:ns0="http://schemas.microsoft.com/BizTalk/EDI/X12/2006">
我不知道如何在伪 XPATH 中指示 XPATH
/ins0:X12InterchangeXml[@xmlns:ins0="http://schemas.microsoft.com/BizTalk/EDI/X12/2006/InterchangeXML"]/FunctionalGroup[@DocType="http://schemas.microsoft.com/BizTalk/EDI/X12/2006#X12_00401_856"]/TransactionSet[@DocType="http://schemas.microsoft.com/BizTalk/EDI/X12/2006#X12_00401_856"]/ns0:X12_00401_856[@xmlns:ns0="http://schemas.microsoft.com/BizTalk/EDI/X12/2006"]/ns0:HLLoop1[1]/ns0:N1Loop1/ns0:N1/N104/text()
同时还让 XSLT 支持 XPATH,这些 XPATH 基本上是:
/ins0:X12InterchangeXml[@xmlns:ins0="http://schemas.microsoft.com/BizTalk/EDI/X12/2006/InterchangeXML"]/ns0:ISA[@xmlns:ns0="http://schemas.microsoft.com/Edi/X12ServiceSchema"]/ISA01/text()
最佳答案
在您的样式表中,您可以使用您喜欢和需要的任何前缀,您不需要使用与输入 XML 相同的前缀,您只需确保将前缀绑定(bind)到与输入元素相同的命名空间 URI选择。因此,如果您在输入中使用了具有不同 namespace URI 的相同前缀,那么在您的 XSLT 中,使用绑定(bind)到第二个 URI 的不同前缀,并在 XPath 中在需要的地方使用第二个前缀,例如xmlns:ns0="http://schemas.microsoft.com/Edi/X12ServiceSchema" xmlns:ns2="http://schemas.microsoft.com/BizTalk/EDI/X12/2006"
作为 XSLT 中的命名空间声明,然后在 XPath 表达式中使用这些前缀。
关于xml - 具有相同 namespace 名称、不同 URI 的 XML 的 XSLT,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48290645/