我在 python 中有以下代码
from scipy.io.wavfile import read
rate, signal = read('./data/input.wav')
# get only one channel
signal = signal[:,0]
# do a bunch of processing here
现在我想使用“信号”和“速率”创建一个 pydub 段
audio_segment = pydub.AudioSegment()
那么我怎样才能创建这个音频片段,然后, 我怎样才能以 numpy 数组的形式取回我的信号?
最佳答案
我能够在我的机器上运行此代码:
from scipy.io.wavfile import read
from pydub import AudioSegment
rate, signal = read("./test/data/test1.wav")
channel1 = signal[:,0]
audio_segment = pydub.AudioSegment(
channel1.tobytes(),
frame_rate=rate,
sample_width=channel1.dtype.itemsize,
channels=1
)
# test that it sounds right (requires ffplay, or pyaudio):
from pydub.playback import play
play(audio_segment)
关于python - 如何使用 numpy 数组创建 pydub AudioSegment?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35735497/