我能够获取
一个ListView
并显示任何列表项的详细信息页面onPress
。我可以在 DetailsPage
中显示单击项目的详细信息,但只能在 render()
中显示。如何访问渲染之外的任何值?我想使用该值从另一个 API 中获取
信息
主页:
import React, { Component } from 'react';
import {
AppRegistry, StyleSheet, ListView,
Text, TouchableHighlight, View
} from 'react-native';
import { StackNavigator } from 'react-navigation';
import DetailsPage from './src/DetailsPage';
class HomeScreen extends React.Component {
static navigationOptions = {
title: 'MyApp!',
};
constructor() {
super();
const ds = new ListView.DataSource({rowHasChanged: (r1, r2) => r1 !== r2});
this.state = {
userDataSource: ds,
};
}
componentDidMount(){
this.fetchUsers();
}
fetchUsers(){
fetch('https://jsonplaceholder.typicode.com/users')
.then((response) => response.json())
.then((response) => {
this.setState({
userDataSource: this.state.userDataSource.cloneWithRows(response)
});
});
}
renderRow(user, sectionID, rowID, highlightRow){
const { navigate } = this.props.navigation;
return(
<TouchableHighlight onPress={() => navigate('DetailsPage', {users:user })}>
<View style={styles.row}>
<Text style={styles.rowText}> {user.name} </Text>
</View>
</TouchableHighlight>
)
}
render(){
return(
<ListView
dataSource = {this.state.userDataSource}
renderRow = {this.renderRow.bind(this)}
/>
)
}
}
const NavigationTest = StackNavigator({
Home: { screen: HomeScreen },
DetailsPage: { screen:DetailsPage },
});
AppRegistry.registerComponent('NavigationTest', () => NavigationTest);
详细信息页面:
import React, { Component } from 'react';
import { StyleSheet, ListView, Text, TouchableHighlight, View } from 'react-native';
export default class DetailsPage extends React.Component {
static navigationOptions = ({ navigation }) => ({
title: `${navigation.state.params.users.name}`,
});
// var userid = 2; --> This doesn't work as it returns Unexpected Token where var is mentioned.
constructor() {
super();
const ds = new ListView.DataSource({rowHasChanged: (r1, r2) => r1 !== r2});
this.state = {
albumDataSource: ds,
};
}
componentDidMount(){
this.fetchAlbums();
}
fetchAlbums(){
var theUser = 2; //This is the value I want to receive from the clicked user.
// var newUser = this.props.navigation.state.users.id; -> this doesnt work.
fetch('https://jsonplaceholder.typicode.com/albums?userId='+newUser)
.then((response) => response.json())
.then((response) => {
this.setState({
albumDataSource: this.state.albumDataSource.cloneWithRows(response)
});
});
}
renderRow(album, sectionID, rowID, highlightRow){
return(
<TouchableHighlight>
<View style={styles.row}>
<Text style={styles.rowText}> {album.userId} - {album.title} </Text>
</View>
</TouchableHighlight>
)
}
render() {
const { params } = this.props.navigation.state;
return (
<View style={styles.container}>
<Text style={styles.textstyle}>Screen Chat with {params.users.name}</Text>
<Text style={styles.textstyle}>Username : {params.users.username}</Text>
<Text style={styles.textstyle}>Email : {params.users.email}</Text>
<Text style={styles.textstyle}>ID : {params.users.id}</Text>
<ListView
dataSource = {this.state.albumDataSource}
renderRow = {this.renderRow.bind(this)}
/>
</View>
);
}
}
因此,我想使用 users.id
在 DetailsPage
上获取更多数据并显示该数据。我怎么做。请帮忙。非常感谢。
最佳答案
这是我发现的,这对我来说看起来是错误的,
var newUser = this.props.navigation.state.users.id;
使用这个也许可以帮助你
console.log(this.props.naviagtion.state.params) **Check if are getting those value then use below one **
var newUser = this.props.navigation.state.params.users.id;
关于reactjs - 使用渲染外部的堆栈导航访问 channel 数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45412351/