java - 计算字符串列表中的元音并打印计数

Question

我有一个代码必须仅打印数组列表中字符串中的元音，但我不确定我的方法是否正确。我该如何解决这个问题？它只打印出其中 5 个，因为我不确定如何直接获取每个特定的元音。请找到我尝试过的以下代码。

import java.util.*;

public class vowels {

    public static void main(String[] args) {

        ArrayList<String> vowels = new ArrayList<String>();

        vowels.add("mitsubishi");
        vowels.add("subaru");
        vowels.add("nissan");
        vowels.add("honda");
        vowels.add("toyota");


        averageVowels(vowels);
    }

    public static void averageVowels(ArrayList<String> vowels) {

        System.out.println(vowels);

        int number = 0;

        for (int i = 0; i < vowels.size(); i++)
        {
            if (vowels.get(i).contains("a") || vowels.get(i).contains("e") || vowels.get(i).contains("i") ||vowels.get(i).contains("o") || vowels.get(i).contains("u"))
            {
                number++;
            }
        }
        System.out.println("a count: " +number);
        System.out.println("e count: " +number);
        System.out.println("i count: " +number);
        System.out.println("o count: " +number);
        System.out.println("u count: " +number);
    }
}

Answer 1

你可以在没有任何循环的情况下完成，非常容易

public static void averageVowels(ArrayList<String> vowels) {
    System.out.println(vowels);
    String arrayToString = vowels.toString();
    int length = arrayToString.length();
    System.out.println("a count: " + (length - arrayToString.replace("a", "").length()));
    System.out.println("e count: " + (length - arrayToString.replace("e", "").length()));
    System.out.println("i count: " + (length - arrayToString.replace("i", "").length()));
    System.out.println("o count: " + (length - arrayToString.replace("o", "").length()));
    System.out.println("u count: " + (length - arrayToString.replace("u", "").length()));
}

打印

[mitsubishi, subaru, nissan, honda, toyota]
a count: 4
e count: 0
i count: 4
o count: 3
u count: 3