Java 正则表达式通配符不被接受

Question

String depends2 = "success(job1) AND n(job2)";
depends2  = depends2.replaceAll("[\\s].(?i)[snd][\\s]*\\(", "");     
System.out.println(depends2);

我希望输出

success(job1) ANDjob2)

相反，它输出

success(job1) AND n(job2)

Answer 1

[\\s].(?i)[snd] 正则表达式中的这可确保空格和 n 之间必须有一个字符 (后跟零个或多个空格加上 ( 符号)。但实际上没有字符。因此您的正则表达式失败并返回原始字符串而不进行任何替换。

String depends2 = "success(job1) AND n(job2)";
depends2  = depends2.replaceAll("\\s(?i)[snd]\\s*\\(", "");     
System.out.println(depends2);

输出:

success(job1) ANDjob2)

说明:

\s                       whitespace (\n, \r, \t, \f, and " ")
(?i)                     set flags for this block (case-
                         insensitive) (with ^ and $ matching
                         normally) (with . not matching \n)
                         (matching whitespace and # normally)
[snd]                    any character of: 's', 'n', 'd'
\s*                      whitespace (\n, \r, \t, \f, and " ") (0 or
                         more times)
\(                       '('