javascript - 使用 jquery 将 yii2 ajax 请求中的两个参数传递给 Controller

Question

我有一个链接，按下时它通过渲染ajax从 Controller 请求页面，以前我只传递id，但现在我想向 Controller 传递一个额外的参数，我如何实现这一点， 这是我尝试过的

这是仅将单个参数传递给 Controller ​​的链接

Html::a('click me', ['#'],
['value' => Url::to('checktruck?id='.$model->id), //this is where the param is passed 
'id' => 'perform']);

这是需要 2 个参数的 Controller 代码:

public function actionChecktruck($id,$category)  //it expects 2 parameters from above link
{
     $truckdetails = Truck::find()->where(['id' =>$id])->one();

    if (Yii::$app->request->post()) {
      $checklistperform = new TodoTruckChecklist();
        $truck = Truck::find()->where(['id'=>$id])->one();
        $checklistperform->truck_id=$id;
        $checklistperform->registered_by=Yii::$app->user->identity->id;
        $checklistperform->save();
        $truck->update();

        var_dump($checklistperform->getErrors());
        //var_dump($truck->getErrors());
    }
    else {
        $truckcategory = Checklist::find()->where(['truck_category'=>$truckdetails->truck_category])->andWhere(['checklist_category'=>$category])->all();
        return $this->renderAjax('truckyard/_checklistform', [
            'truckcategory' => $truckcategory,'truckvalue'=>$id,
        ]);

    }

}

这是我的另一个按钮的 jquery 代码，该按钮在发布请求期间依赖于上述 Controller

$("#postbutn").click(function(e) {

   $.post("checktruck?id="+truckid,  //here i would like to pass 2 params
                {checked:checked,unchecked:unchecked,truckid:truckid}
            )
 }

这是没有post时的jquery代码

我如何在链接中传递额外的参数，甚至是 Controller 的 $.post 请求

Answer 1

首先，由于您使用JQuery ajax提交表单，因此不需要为链接设置值

Html::a('click me', ['#'],['id' => 'perform']);

使用此 ID，您可以按如下方式提交请求

$this->registerJs("$('#perform').click(function(event){

event.preventDefault(); // to avoid default click event of anchor tag

$.ajax({
    url: '".yii\helpers\Url::to(["your url here","id"=>$id,"param2"=>param2])."',        
    success: function (data) {
           // you response here
        },
      });
});");

方法属性不需要指定为“POST”，您想通过 GET 方法发送

最后在你的 Controller 中，你需要接受如下参数

public function actionChecktruck()  //it expects 2 parameters from above link
{
     $id = Yii::$app->request->queryParams['id'];
     $param2 = Yii::$app->request->queryParams['param2'];

     $truckdetails = Truck::find()->where(['id' =>$id])->one();

    if (Yii::$app->request->post()) {
      $checklistperform = new TodoTruckChecklist();
        $truck = Truck::find()->where(['id'=>$id])->one();
        $checklistperform->truck_id=$id;
        $checklistperform->registered_by=Yii::$app->user->identity->id;
        $checklistperform->save();
        $truck->update();

        var_dump($checklistperform->getErrors());
        //var_dump($truck->getErrors());
    }
    else {
        $truckcategory = Checklist::find()->where(['truck_category'=>$truckdetails->truck_category])->andWhere(['checklist_category'=>$category])->all();
        return $this->renderAjax('truckyard/_checklistform', [
            'truckcategory' => $truckcategory,'truckvalue'=>$id,
        ]);

    }

}