我有以下 MySQL 查询:
$query_waitingrooms = "SELECT * FROM waitingroom, waitingroom_case_lookup, vcase, patient WHERE vcase.patient_fk = patient.patient_pk AND waitingroom.waitingroom_pk = waitingroom_case_lookup.waitingroom_fk AND vcase.case_pk = waitingroom_case_lookup.case_fk AND vcase.active = 'y' AND vcase.case_pk NOT IN (SELECT case_fk FROM user_case_lookup WHERE user_id = '$user_id')";
$result_waitingrooms = mysql_query($query_waitingrooms, $connection) or die(mysql_error());
打印结果:
while ($row_waitingrooms = mysql_fetch_assoc($result_waitingrooms)){
echo "<h6>" . $row_waitingrooms['waitingroom'] . "</h6><div><p><span class='text'><table width='100%'><tr><td><input name='case' id='case_" . $row_waitingrooms['case_pk'] . "' type='radio' value='" . $row_waitingrooms['case_pk'] . "' /></td><td width='65' align='left'><div class='case_list'><img src='images/case_icons/" . $row_waitingrooms['patient_icon'] . "' width='44' height='45' /></div></td><td width='350' align='left'>" . $row_waitingrooms['first_name'] . ' ' . $row_waitingrooms['last_name'] . '  Gender: ' . $row_waitingrooms['gender'] . ' Age: ' . $row_waitingrooms['age'] . '<br />Presenting Complaint: ' . $row_waitingrooms['presenting_complaint'] . "</td></tr></table></p></div>";
}
正如预期的那样，这会为表“waitingroom_case_lookup”中的每条记录生成一个折叠面板，每个折叠面板包含一个“案例”。我想要的是为每个“候诊室”提供一个 Accordion ，并且每个“候诊室”都包含来自表 vcase 和 Patient 的相关病例数据。
目前表“waitingroom_case_lookup”是:
CREATE TABLE waitingroom_case_lookup (
waitingroom_case_lookup_pk int(9) NOT NULL AUTO_INCREMENT,
waitingroom_fk int(3) NOT NULL,
case_fk int(3) NOT NULL,
PRIMARY KEY (waitingroom_case_lookup_pk)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
--
-- Dumping data for table 'waitingroom_case_lookup'
--
INSERT INTO waitingroom_case_lookup (waitingroom_case_lookup_pk, waitingroom_fk, case_fk) VALUES
(1, 1, 1),
(2, 1, 2),
(3, 2, 3);
看来我需要循环出 <span class='text'> 之间每个 Accordion 等候室的箱子。和</p></div>有什么建议我可以如何做到这一点吗？
编辑
感谢 NoBBY，我有以下工作代码(仍然需要清理重新格式化...):
<?php
while ($row_waitingrooms = mysql_fetch_assoc($result_waitingrooms)){
$waitingRoomPK = $row_waitingrooms['waitingroom_pk'];
if (!isset($waitingRooms[$waitingRoomPK])) {
$waitingRooms[$waitingRoomPK] = array(
'waitingroom_pk' => $waitingRoomPK,
'waitingroom' => $row_waitingrooms['waitingroom'],
'cases' => array()
);
}
$waitingRooms[$waitingRoomPK]['cases'][] = array(
'case_pk' => $row_waitingrooms['case_pk'],
'patient_icon' => $row_waitingrooms['patient_icon'],
'first_name' => $row_waitingrooms['first_name'],
'last_name' => $row_waitingrooms['last_name'],
'age' => $row_waitingrooms['age']
);
echo "<h6>" . $row_waitingrooms['waitingroom'] . "</h6><div><p><span class='text'>";
foreach ($waitingRooms[$waitingRoomPK]['cases'] as $wcase){
echo "<table width='100%'><tr><td><input name='case' id='case_" . $wcase['case_pk'] . "' type='radio' value='" . $wcase['case_pk'] . "' /></td><td width='65' align='left'><div class='case_list'><img src='images/case_icons/" . $wcase['patient_icon'] . "' width='44' height='45' /></div></td><td width='350' align='left'>" . $wcase['first_name'] . ' ' . $wcase['last_name'] . '  Gender: ' . $wcase['gender'] . ' Age: ' . $wcase['age'] . '<br />Presenting Complaint: ' . $wcase['presenting_complaint'] . "</td></tr></table>";
}
echo "</span></p></div>";
}
?>
最佳答案
不要直接从数据库输出结果，而是先尝试格式化它。 例如，您可以这样做:
$waitingRooms = array();
while ($row_waitingrooms = mysql_fetch_assoc($result_waitingrooms)){
$waitingRoomPK = $row_waitingrooms['waitingroom_pk'];
if (!isset($waitingRooms[$waitingRoomPK])) {
$waitingRooms[$waitingRoomPK] = array(
'waitingroom_pk' => $waitingRoomPK,
'waitingroom' => $row_waitingrooms['waitingroom'],
'cases' => array(),
//.....all the data for a waitingroom
);
}
$waitingRooms[$waitingRoomPK]['cases'][] = array(
'case_pk' => $row_waitingrooms['case_pk'],
'patient_icon' => $row_waitingrooms['patient_icon'],
'first_name' => $row_waitingrooms['first_name'],
//.......all the data for a patient
);
}
现在 $waitingRooms 是包含每个候诊室数据的数组，以及包含房间中每个患者数据的“cases”子数组 从这里开始，两个简单的嵌套 foreach 语句将输出 Accordion 所需的 html
这里有一些改进代码的方法:
- 不要使用 mysql_* 函数，它们已被弃用。文档中那些巨大的红色警告不仅仅是为了美观。用户 mysqli 或 PDO(均在文档中链接)
- 使用实际的联接，查询中的替代联接语法会损害可读性
- 格式化您的 sql 和 html 代码。我敢打赌，很多人在代码段中看到这些水平滚动条时都跳过了您的问题
我希望您同意:
<?php while($row_waitingrooms = mysql_fetch_assoc($result_waitingrooms)): ?>
<h6><?= $row_waitingrooms['waitingroom']; ?></h6>
<div>
<p>
<span class='text'>
<table width='100%'>
<tr>
<td>
<input name='case' id='case_<?= $row_waitingrooms['case_pk']; ?>' type='radio' value='<?= $row_waitingrooms['case_pk']; ?>' />
</td>
<td width='65' align='left'>
<div class='case_list'>
<img src='images/case_icons/<?= $row_waitingrooms['patient_icon']; ?>' width='44' height='45' />
</div>
</td>
<td width='350' align='left'>
<?= $row_waitingrooms['first_name'] . ' ' . $row_waitingrooms['last_name']; ?>
Gender: <?= $row_waitingrooms['gender']; ?>
Age: <?= $row_waitingrooms['age']; ?>
<br />
Presenting Complaint: <?= $row_waitingrooms['presenting_complaint']; ?>
</td>
</tr>
</table>
</p>
</div>
<?php endwhile; ?>
比这更好:
while ($row_waitingrooms = mysql_fetch_assoc($result_waitingrooms)){
echo "<h6>" . $row_waitingrooms['waitingroom'] . "</h6><div><p><span class='text'><table width='100%'><tr><td><input name='case' id='case_" . $row_waitingrooms['case_pk'] . "' type='radio' value='" . $row_waitingrooms['case_pk'] . "' /></td><td width='65' align='left'><div class='case_list'><img src='images/case_icons/" . $row_waitingrooms['patient_icon'] . "' width='44' height='45' /></div></td><td width='350' align='left'>" . $row_waitingrooms['first_name'] . ' ' . $row_waitingrooms['last_name'] . '  Gender: ' . $row_waitingrooms['gender'] . ' Age: ' . $row_waitingrooms['age'] . '<br />Presenting Complaint: ' . $row_waitingrooms['presenting_complaint'] . "</td></tr></table></p></div>";
}
并且您将获得奖励以查看未闭合的跨度标签:)
关于PHP 在单独的 JQuery Accordion 中循环出记录，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/19536678/