javascript - 循环对象时出现问题

Question

我有从 HTML 表创建的对象，每个对象都是该表中的一行。它们看起来像这样:

function rowObj(aName,suctionTemp,liquidTemp,outsideTemp,boxTemp,foodTemp1,foodTemp2,foodTemp3,foodTemp4,suctionPsi,liquidPsi,
            compressorAmps,condensorFan,evaporatorFan,mainPower,doorSwitch,input2,input3,input4,hour,minute,amPm){
this.aName=aName,
    this.suctionTemp=suctionTemp,
    this.liquidTemp=liquidTemp,
    this.outsideTemp=outsideTemp,
    this.boxTemp=boxTemp,
    this.foodTemp1=foodTemp1,
    this.foodTemp2=foodTemp2,
    this.foodTemp3=foodTemp3,
    this.foodTemp4=foodTemp4,
    this.suctionPsi=suctionPsi,
    this.liquidPsi=liquidPsi,
    this.compressorAmps=compressorAmps,
    this.condensorFan=condensorFan,
    this.evaporatorFan=evaporatorFan,
    this.mainPower=mainPower,
    this.doorSwitch=doorSwitch,
    this.input2=input2,
    this.input3=input3,
    this.input4=input4,
    this.hour=hour,
    this.minute=minute,
    this.amPm=amPm;

};

我想做的是循环这些对象并获取设备打开的时间。我可以通过以下方式做到这一点:

var minuteArray=[];
for ( var key in objects){
    if (objects[key].compressorAmps > 0 && objects[key].condensorFan > 0){
        minuteArray.push(objects[key].minute);
    }else{
        key++;
        break;
    }
}
var firstMinute= minuteArray.shift();
var lastMinute=minuteArray.pop();

var hourArray=[];
for ( var key in objects){
    if (objects[key].compressorAmps > 0 && objects[key].condensorFan > 0){
        hourArray.push(objects[key].hour);
    }else{
        key++;
        break;
    }
}
var firstHour= hourArray.shift();
var lastHour=hourArray.pop();

在这里，我将所有值插入一个数组，然后取出第一个和最后一个元素，并从中获取小时和分钟。这使我可以计算它已经运行了多长时间。这也只给我当前的运行时间。最终我想: 1. 将每组运行值存储在数组中 2.然后是数组中等于0时的值 3. 然后继续并将下一组 > 0 的位置存储在不同的数组中

    for ( key in objects){
    if ( objects[key].compressorAmps > 0 && objects[key].condensorFan > 0){
        //store values in an array until compressorAmps === 0, skip those
        //then store the next set, where compressorAmps >0 in a different array
    }else if (objects[key].compressorAmps === 0 && objects[key].condensorFan === 0){

    }
}

我不知道这是否可能，如果可能，我很难弄清楚。任何帮助将不胜感激。谢谢

Answer 1

将您的值放入按时间排序的数组中(我认为这就是您想要的)。然后您需要做的就是迭代数组，测试每个值并查找边缘条件。所以类似:

var result = [];    // this will be a 2D array with your results
var curr = null;    // this is the current run
for (var i=0; i < data.length; i++) {
     if (data[i].compressorAmps > 0) {   // test condition, change as needed
         if (!curr) {                    // if we don't have a run, start one
             curr = [];
         }
         curr.push(data[i]);             // store the current value
     } else {
        if (curr) {                      // if this is the end of a run
            result.push(curr);           // save the run
            curr = null;
        }
     }
}

现在您可以迭代结果并获取每次运行的第一次和最后一次来计算时间:

for (var i=0; i < result.length; i++) {
    var start = result[i][0];
    var end = result[i][result[i].length - 1];
    console.log("Run started at: " + start.hour + ":" start.minute);
    console.log("Run ended at: " + end.hour + ":" end.minute);
}