使用此 JSON，自动化 JSON 到 POJO 会严重失败。
请注意，一项请求的项目数量与另一项请求的项目数量不同。 在这里，我包含了包含 2 个项目的 JSON 响应。
{
"status": 1,
"complete": 1,
"list": {
"734233858": {
"item_id": "734233858",
"resolved_id": "734233858",
"given_url": "https://blog.openshift.com/developing-single-page-web-applications-using-java-8-spark-mongodb-and-angularjs/",
"given_title": "",
"favorite": "0",
"status": "0",
"time_added": "1466459879",
"time_updated": "1466459862",
"time_read": "0",
"time_favorited": "0",
"sort_id": 1,
"resolved_title": "Developing Single Page Web Applications using Java 8, Spark, MongoDB, and AngularJS",
"resolved_url": "https://blog.openshift.com/developing-single-page-web-applications-using-java-8-spark-mongodb-and-angularjs/",
"excerpt": "In this post you will learn how to use a micro framework called Spark to build a RESTful backend. The RESTful backend is consumed by a single page web application using AngularJS and MongoDB for data storage. I’ll also show you how to run Java 8 on OpenShift.",
"is_article": "1",
"is_index": "0",
"has_video": "0",
"has_image": "1",
"word_count": "2727"
},
"1015284226": {
"item_id": "1015284226",
"resolved_id": "1015284226",
"given_url": "https://sparktutorials.github.io/2015/08/04/spark-video-tutorials.html",
"given_title": "",
"favorite": "0",
"status": "0",
"time_added": "1466458750",
"time_updated": "1466458737",
"time_read": "0",
"time_favorited": "0",
"sort_id": 0,
"resolved_title": "Spark Video Tutorials",
"resolved_url": "http://sparktutorials.github.io/2015/08/04/spark-video-tutorials.html",
"excerpt": "Our friends over at learnhowtoprogram.com have been working on a series of Java courses for beginners, all of which feature Spark. This post contains an overview of these courses with direct links to their videos.",
"is_article": "1",
"is_index": "0",
"has_video": "0",
"has_image": "0",
"word_count": "41"
}
},
"error": null,
"search_meta": {
"search_type": "normal"
},
"since": 1509309762
}
这个 JSON 对象的 POJO 会是什么样子？
最佳答案
你无法解析出list因为数字是随机的，所以对象相当好。您需要将其制作为 map 。否则，其余数据可由 Gson 解析。
class Foo {
int status;
int complete;
TreeMap<String, Object> list;
Object error;
SearchMeta search_meta;
long since;
}
class SearchMeta {
String search_type;
}
您可以替换 <String, Object> map <String, InnerObject> ，其中InnerObject是该对象的 POJO
{
"item_id": "734233858",
"resolved_id": "734233858",
"given_url": "https://blog.openshift.com/developing-single-page-web-applications-using-java-8-spark-mongodb-and-angularjs/",
"given_title": "",
"favorite": "0",
...
关于java - 如何将这个 JSON 响应转换为 POJO？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/47188934/