php - Laravel 的 Response 内容必须是字符串或对象实现 __toString(), "object"given

Question

我想运行技能功能，但我做不到。

路由.php

Route::get('setting',function(){
    return \App\User::first()->skills();
});

用户.php

protected $casts = [
    'skills' => 'json'
];

public function skills(){
    return new Skills($this , $this->skills);
}

技能.php

namespace App;
use App\User;
use Mockery\Exception;

class Skills
{
    protected $user;
    protected $skills = [];

    public function __construct(User $user,array $skills){

        $this->user=$user;
        $this->skills=$skills;
    }
}

我想进入/settings 页面我有“The Response content must be a string or object implementing __toString(), "object"given.”错误。

我试图在路由中添加 dd() 函数的返回值，我看到了所有 JSON 数据，但 $skills->get(), $skill-> set() 当时没有工作。

编辑:

技能.php

<?php
    /**
     * Created by PhpStorm.
     * User: root
     * Date: 01.08.2015
     * Time: 11:45
     */

    namespace App;
    use App\User;
    use Mockery\Exception;

    class Skills
    {
        protected $user;
        protected $skills = [];

        public function __construct(User $user,array $skills){
            $this->user=$user;
            $this->skills=$skills;
        }

        public function get($key){
            return array_get($this->skills,$key);
        }

        public function set($key,$value){
            $this->skills[$key]=$value;
            return $this->duration();
        }

        public function has($key){
            return array_key_exists($key,$this->skills);
        }

        public function all(){
           return $this->skills;
        }

        public function merge(array $attributes){
            $this->skills = array_merge(
                $this->skills,
                array_only(
                    $attributes,
                    array_keys($this->skills)
                )
            );
            return $this->duration();
        }

        public function duration(){
            return $this->user->update(['skills' => $this->skills]);
        }

        public function __get($key){
            if ($this->has($key)) {
                return $this->get($key);
            }
            throw new Exception("{$key} adlı Yetenek bulunamadı");
        }
    }

Answer 1

当你做的时候

return \App\User::first()->skills();

您返回的是 Relation 定义对象，它没有实现 __toString() 方法。返回相关对象所需的是

return \App\User::first()->skills;

这将返回一个包含相关技能的Collection对象——这将被正确序列化。