在查找两个 SQL 日期之间的差异时，我得到了错误的天数。 方法如下:
public Vector getAvailRoom(String RoomID)
{
formatter = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
Date dateA = null;
Date dateD = null;
Vector vect = new Vector();
try
{
psmt=con.prepareStatement("select * from Booking where RmID="+RoomID);
rs=psmt.executeQuery();
while(rs.next())
{
AvailDetails2 avaDet = new AvailDetails2();
avaDet.BookArrivalDate = rs.getString("BookArrivalDate");
avaDet.BookDepartureDate = rs.getString("BookDepartureDate");
System.out.println(""+avaDet.BookArrivalDate);
System.out.println(""+avaDet.BookDepartureDate);
try
{
dateA = (Date) formatter.parse(avaDet.BookArrivalDate);
dateD = (Date) formatter.parse(avaDet.BookDepartureDate);
DateTime datetimeA = new DateTime(dateA);
DateTime datetimeD = new DateTime(dateD);
diffDays = Days.daysBetween(datetimeA.toLocalDate(), datetimeD.toLocalDate()).getDays();
System.out.println(""+diffDays);
avaDet.BookDiffDays = Integer.toString(diffDays);
}
catch (Exception egetAvailRoom)
{
egetAvailRoom.printStackTrace();
}
vect.add(avaDet);
}
}
catch (Exception e3)
{
}
return vect;
}//end getAvailRoom
假设
BookArrivalDate 是 2013-10-01 00:00:00
和
BookDepartureDate 为 2013-10-14 00:00:00
我得到 4748 的差额。
最佳答案
这就是问题:
formatter = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
按照日、月、年的顺序查看您的格式 - 然后查看您的数据。我相信你想要:
formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
(我还鼓励您改用 Joda Time 格式化类...)
关于java - 使用 JodaTime 获取错误的天数，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/19251262/