mysql - COUNT 与 RANK mysql

Question

我想从我的数据库中获取员工的姓氏，比他收入高的员 worker 数，然后将员工的薪水降序排列；收入最高的员工为零。这是我的做法:

SELECT 0+COUNT(b.salary) rank
, a.lname
, a.salary
, COUNT(*) AS employee_count
FROM employee a LEFT OUTER JOIN employee b
ON a.salary<b.salary
GROUP BY a.salary, a.lname
ORDER BY salary DESC

结果如下所示:

到目前为止一切顺利。除了，博格甚至不应该在那里。因为没有人比他挣得更​​多。现在发生这种情况是因为使用了 LEFT OUTER JOIN。我尝试使用 INNER JOIN 但它给出了语法错误。所以问题是我怎样才能让 INNER JOIN 与它一起工作？

Answer 1

如果只想去掉最高值:

SELECT *
FROM (    
    SELECT 0+COUNT(b.salary) rank
        , a.lname
        , a.salary
        , COUNT(*) AS employee_count
    FROM employee a 
    LEFT OUTER JOIN employee b
        ON a.salary < b.salary
    GROUP BY a.salary, a.lname
    ORDER BY salary DESC
) T1
WHERE T1.rank > 0