Java 我该如何解析这个？

Question

我有一个文件，内容如下:

J1  0   90  "7,27,73,86"
J2  1   39  "12"
J3  2   195 "11,31,73,94,120,134,183"

我将第四列数字存储为字符串

 Scanner input = new Scanner( new File( "projectData.txt" ) );

      while ( input.hasNext() )
      {
        job =  input.next();//
        arrival = input.nextInt();//
        cpu = input.nextInt();
        fault = input.next();   

        jobs[i] = new MyJobs( job, arrival, cpu, fault );//stores four local variables in array
        i++;//increments I

如何解析字符串以将它们存储为整数，以便稍后将它们与我的 cpu 值进行比较？

Answer 1

基本方法是使用 String.substring() 删除双引号，然后使用 String.split() 将逗号插入 String[]。从这里您就知道 int[] 需要有多大，因此只需迭代 String[] 并将每个元素转换为 int .

public static void main(String[] args) throws Exception {
    String fault = "\"11,31,73,94,120,134,183\"";
    String[] pieces = fault.substring(1, fault.length() - 1).split(",");

    int[] faultNumbers = new int[pieces.length];
    for (int i = 0; i < faultNumbers.length; i++) {
        faultNumbers[i] = Integer.parseInt(pieces[i]);
    }

    System.out.println(Arrays.toString(faultNumbers));
}

结果:

[11, 31, 73, 94, 120, 134, 183]

Java 8 流

为了使用流构建 @alfasin 答案，可以缩短基本方法。

public static void main(String[] args) throws Exception {
    String fault = "\"11,31,73,94,120,134,183\"";
    String[] pieces = fault.substring(1, fault.length() - 1).split(",");

    // This does the job of the for loop in the basic approach
    int[] faultNumbers = Arrays.stream(pieces)
            .mapToInt(Integer::parseInt)
            .toArray();

    System.out.println(Arrays.toString(faultNumbers));
}