java - 将 Xml 布局到我的 Android 应用程序

Question

早上好!所以我有这个

MainActivity.java

import......

public class MainActivity extends Activity {


@Override
public void onCreate(Bundle savedInstanceState){
  super.onCreate(savedInstanceState);
  setContentView(R.layout.activity_main);
  getXmlTask task = new getXmlTask(textview1 , "http://www.3pi.tf/test.xml");
  task.execute(); 
 }
} 

这是我的 getXmlTask​​.java

import....etc

public class getXmlTask extends AsyncTask<Void, Void, String>{
    private static final String TAG2 = null;

    private WeakReference<TextView> textViewReference;
    private String url;

    public void GetXmlTask(TextView textView, String url) {
        this.textViewReference = new WeakReference<TextView>(textView);
        this.url = url;
    }

    @Override
    protected String doInBackground(Void... params) {
        HttpClient hc = new DefaultHttpClient();
        Log.v(TAG2, "testnew");
        HttpPost post = new HttpPost(url);
        Log.v(TAG2, "testurl");
        HttpResponse rp = null;
        try {
            rp = hc.execute(post);
        } catch (ClientProtocolException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        Log.v(TAG2, "testpost");

        if(rp.getStatusLine().getStatusCode() == HttpStatus.SC_OK)
        {
            try {
                return EntityUtils.toString(rp.getEntity());
            } catch (ParseException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }
        return "Error";
    }   

    @Override
    protected void onPostExecute(String result) {       
        TextView textView = textViewReference.get();
        if(textView != null) {
            textView.setText(result);
        }       
    }

}

getXmlTask​​.java 上没有错误，但我在线上遇到此错误

getXmlTask task = new getXmlTask(textview1 , "http://www.3pi.tf/test.xml");

它说“textview1无法解析为变量”...但我在我的mainlayout.xml上“+id”.. 抱歉，我刚刚开始 Android 开发，再次抱歉我的英语 ^^

Answer 1

textview1 应该是 MainActivity 中的一个变量，例如

TextView textview1 = (TextView) findViewById(R.id.textview1);

然后将 textview1 传递给您的 getXmlTask​​