所以我有一个 aspx 页面，它为客户端提供 XML + XSL 服务，并进行客户端转换，效果很好。
我正在尝试检测客户端，如果他们不支持客户端转换，我会在服务器端进行。我正在中断渲染处理器返回 XML 的 aspx 页面，我正在获取它的输出，将它与 XSL 页面的输出相结合并提供出去。但是，此输出格式不正确。我明白了
XML Parsing Error: mismatched tag. Expected: </link>.
Location: http://oohrl.com/dashboard.aspx
Line Number 36, Column 20: </script></head>
-------------------^
在客户端生成的输出中，效果很好，例如，我得到
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/>
<link rel="stylesheet" type="text/css" href="./css/dboard.css"/>
<link rel="stylesheet" type="text/css" href="./css/dboardmenu.css"/>
<script type="text/javascript" src="./js/simpletabs.js"/>
<link href="../css/simpletabs.css" rel="stylesheet" type="text/css"/>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6/jquery.min.js"/>
<script type="text/javascript">
$(document).ready(function () {
$("#BlogSelectList li a").live("click", function () {
var str = ($(this).attr("href")).slice(1, 37)
$.ajax({
contentType: "application/json; charset=utf-8",
url: '../ws/WebServices.asmx/SetActiveBlog',
data: '{ActiveBlogID: "' + str + '"}',
dataType: 'json',
type: "post",
success: function (j) {
window.location.href = 'dashboard.aspx'
}
});
});
})
function showlayer(layer) {
var myLayer = document.getElementById(layer);
if (myLayer.style.display == "none" || myLayer.style.display == "") {
myLayer.style.display = "block";
}
else {
myLayer.style.display = "none";
}
}
</script></head>
如果我在服务器端生成它，我会得到
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
<head>
<META http-equiv="Content-Type" content="text/html; charset=utf-16">
<link rel="stylesheet" type="text/css" href="./css/dboard.css">
<link rel="stylesheet" type="text/css" href="./css/dboardmenu.css">
<script type="text/javascript" src="./js/simpletabs.js"></script>
<link href="../css/simpletabs.css" rel="stylesheet" type="text/css">
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6/jquery.min.js">
</script>
<script type="text/javascript">
$(document).ready(function () {
$("#BlogSelectList li a").live("click", function () {
var str = ($(this).attr("href")).slice(1, 37)
$.ajax({
contentType: "application/json; charset=utf-8",
url: '../ws/WebServices.asmx/SetActiveBlog',
data: '{ActiveBlogID: "' + str + '"}',
dataType: 'json',
type: "post",
success: function (j) {
window.location.href = 'dashboard.aspx'
}
});
});
})
function showlayer(layer) {
var myLayer = document.getElementById(layer);
if (myLayer.style.display == "none" || myLayer.style.display == "") {
myLayer.style.display = "block";
}
else {
myLayer.style.display = "none";
}
}
</script></head>
这给了我错误。当然，我注意到 <link/> 中的差异对比<link>标记，但我不知道为什么服务器端处理引擎给我不同的结果或如何解决它？
这是我用来在服务器上生成 XHTML 的代码
protected override void Render(HtmlTextWriter writer)
{
StringBuilder sb = new StringBuilder();
StringWriter sw = new StringWriter(sb);
HtmlTextWriter hWriter = new HtmlTextWriter(sw);
base.Render(hWriter);
// *** store to a string
string XMLOutput = sb.ToString();
// *** Write it back to the server
if (!Request.Browser.IsBrowser("IE"))
{
writer.Write(XMLOutput);
}
else
{
StringWriter XSLsw = new StringWriter();
HttpContext.Current.Server.Execute("DashboardXSL.aspx", XSLsw);
string output = String.Empty;
using (StringReader srt = new StringReader(XSLsw.ToString())) // xslInput is a string that contains xsl
using (StringReader sri = new StringReader(XMLOutput)) // xmlInput is a string that contains xml
{
using (XmlReader xrt = XmlReader.Create(srt))
using (XmlReader xri = XmlReader.Create(sri))
{
XslCompiledTransform xslt = new XslCompiledTransform();
xslt.Load(xrt);
using (StringWriter _sw = new StringWriter())
using (XmlWriter xwo = XmlWriter.Create(_sw, xslt.OutputSettings)) // use OutputSettings of xsl, so it can be output as HTML
{
xslt.Transform(xri, xwo);
output = _sw.ToString();
}
}
}
writer.Write(output);
Response.Flush();
Response.End();
}
最佳答案
因为你的输出文档的根元素是<html> ，处理器选择 HTML 作为默认格式。要改为创建格式良好的 XHTML 文档，请确保您的 XSLT 包含以下内容作为根的子项 <xsl:stylesheet>或 <xsl:transform>元素:
<xsl:output method="xml" omit-xml-declaration="yes" />
关于c# - 执行服务器端 XML 处理时出错，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/9013357/