java - switch 中的所有情况都会执行，而只有一种情况应该被执行

Question

我正在尝试创建一个非常简单的游戏，其中几个不同类型的玩家尝试猜测一个范围内的数字。我创建了一个函数来初始化玩家数组，并使用 switch-case 来完成它。

由于某种原因，如果我输入一个数字，即使数组中没有足够的单元格，它也会遍历它后面的所有情况。例如，当输入 2(HUMAN 类型的值)时，它也会执行 3 和 4 的情况，并创建 COMPUTER 和 GUMBLER 类型的玩家。

这是代码:

    String name;
    int count = 0;
    System.out.println("How many players will participate?");
    players = new Player[reader.nextByte()];
    for (Player player: players)
    {    
        count++;
        System.out.print("\n1)Name of the player: ");
        name = reader.next();
        System.out.println("What will be its type? WRITE A NUMBER\n1- Monley\n2-Human\n3-Gumbler\n4-Computer");
        switch (reader.nextInt())
        {
            case 1:
                player = new Monkey (name, MAXIMUM, MINIMUM);
                System.out.println("A moneky was created");
            case 2:
                player = new Human (name);
                System.out.println("A human was created");
            case 3:
                player = new Gumbler (name, MAXIMUM, MINIMUM);
                System.out.println("A gummbler was created");
            case 4:
                player = new Computer (name, MAXIMUM, MINIMUM);
                System.out.println("A computer was created");
        }
    }

MAXIMUM和MINIMUM是需要猜测的数字的最小和最大数字。 Human , Monkey , Computer和Gumbler是扩展抽象类的类 Player 。 players是玩家数组(类型为 Player )。

Answer 1

用 break 结束每个 case block 。