javascript - 如何显示从 jQuery 返回的 JSON

Question

如何从 JSON 值获取显示返回值。我需要获取用户 ID 的值

 $('User_id').observe('blur', function(e) {
   var txt = $('User_id').value;
   jQuery.ajax({
     type: 'get',
     url: BASE_URL + 'admin/index/user_id',
     data: {
       user_id: txt
     },
     dataType: 'json',
     success: function(data) {
       console.log('success' + data.success);
       if (data.success) {
         var Value = data.location.user_id;
         alert(Value);
       }
     }
   });
 });

这些值以 html 形式获取。因为我需要将用户 ID 存储在值变量中。但我收到 successundefined 作为输出..

[{
  "user_id": "139",
  "mobile": "9042843911",
  "gender": "male",
  "hashcode": "DfAbMqLApAV6nVa1z940",
  "username": "anandhsp21",
  "password": "74bcff7d1199012e154f364e3f65e31d:8I",
  "authorized_person": "Anandh",
  "created": "2015-06-08 13:46:55",
  "modified": "2015-06-08 06:43:35",
  "logdate": "2015-06-08 08:16:55",
  "lognum": "12",
  "reload_acl_flag": "0",
  "is_active": "1",
  "extra": "N;",
  "rp_token": null,
  "rp_token_created_at": null,
  "app_name": "",
  "api_key": ""
}] 

请有人帮忙。提前致谢

Answer 1

您获取数组中的数据，因此在成功数据中使用循环

for (var i=0; i<data.length; i++) {
    console.log('success' + data[i].user_id );
}

如果知道记录长度为1则直接使用

 console.log('success' + data[0].user_id );