所以我有这个程序需要测试两个矩形并检查:
- 如果测试矩形位于引用矩形内
- 如果测试矩形与引用矩形重叠
- 如果测试矩形仅与引用矩形共享边框
- 如果测试矩形和引用矩形不同
引用矩形和测试矩形均由其中心坐标 (x,y) 及其宽度和高度定义。
我相信我的第一个检查编码正确,但我无法计算出最后三个检查重叠、共享边界和完全不同的数学。
这是迄今为止我的四项检查的代码:
//returns true if the specified rectangle is inside this rectangle
public boolean contains(MyRectangle2D r){
if(this.x > r.x + r.width && x + width < r.x && y > r.y +r.height && y + height < r.y){
return true;
}
else{
return false;
}
}
//returns true if the specified rectangle overlaps with this rectangle
public boolean overlaps(MyRectangle2D r) {
if (this.x < r.x + r.width && x + width > r.x && y < r.y + r.height && y + height > r.y){
return true;
}
else{
return false;
}
}
//returns true if only the boundaries touch
public boolean abut(MyRectangle2D r) {
if(this.x = r.x + r.width && x + width = r.x || y = r.y +r.height && y + height = r.y){
return true;
}
else{
return false;
}
}
//returns true if the rectangles are not touching at all
public boolean distinct(MyRectangle2D r) {
}
最佳答案
您可以使用 Java Topolygy Suite ( JTS ) 来实现:
- 首先,您可以使用
org.locationtech.jts.util.GeometricShapeFactory
( API ) 根据您的参数创建矩形: - 然后您可以使用
org.locationtech.jts.geom.Geometry
( API ) 定义的空间关系(within
、overlaps
...)
简单代码:
// method to create your rectangles like before (Polygon objects)
public static Polygon createPolygon(Coordinate center, double width, double height){
GeometricShapeFactory shapeFactory = new GeometricShapeFactory();
shapeFactory.setNumPoints(4);
shapeFactory.setCentre(center);
shapeFactory.setWidth(width);
shapeFactory.setHeight(height);
return shapeFactory.createRectangle();
}
public static void main(String[] args) {
// create your rectagles
Polygon rectangleA = createPolygon(new Coordinate(0, 0), 5, 10);
Polygon rectangleB = createPolygon(new Coordinate(2, 0), 5, 10);
// ### check your constraints
// 1. rectangle is within the reference rectangle
boolean bWithinA = rectangleB.within(rectangleA); // false
// 2. rectangle is overlapping the reference rectangle
boolean bOverlappingA = rectangleB.overlaps(rectangleA); // true
// 3. rectangle is only sharing a border with the reference rectangle
boolean bSharesBorderA = rectangleB.touches(rectangleA); // false
// 4. rectangle and reference rectangle are distinct
boolean bDistinctsA = rectangleB.disjoint(rectangleA); // false
}
关于java - 如何使用 Java 检查两个矩形几何图形之间的空间关系,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38800229/