我刚刚学习 pygame,遇到了一个问题。我的程序创建了一支外星人舰队,你必须消灭它们。我想在完全移除后立即生成整个舰队,但是当您摧毁另一艘船时,我的程序会立即生成一艘船。
我尝试使用 while len < 48 来限制列表,但没有成功。 这是立即产生外星人的程序(我也在主循环之前插入了它):
def create_fleet(custom_settings, screen, spaceship, aliens):
alien = Alien(custom_settings, screen)
number_aliens_x = get_number_aliens_x(custom_settings, alien.rect.width)
number_rows = get_number_rows(custom_settings, spaceship.rect.height, alien.rect.height) #!!!
for row_number in range(number_rows):
for alien_number in range(number_aliens_x):
if len(aliens) < 48:
create_alien(custom_settings, screen, aliens, alien_number, row_number)
最佳答案
And I want to spawn the whole fleet just after complete removal [...]
因此,一旦外星人数量为 0 ( len(aliens) == 0`),您就必须开始创建外星人舰队,例如:
def create_fleet(custom_settings, screen, spaceship, aliens):
if len(aliens) == 0:
alien = Alien(custom_settings, screen)
number_aliens_x = get_number_aliens_x(custom_settings,alien.rect.width)
number_rows = get_number_rows(custom_settings,spaceship.rect.height,alien.rect.height)
for row_number in range(number_rows):
for alien_number in range(number_aliens_x):
if len(aliens) < 48:
create_alien(custom_settings, screen, aliens, alien_number, row_number)
关于python - 如何限制pygame中的 Sprite 列表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58545878/