我有一个算法可以在单元格中查找值,在本例中,假设单元格是 C10。我需要在 D 列中的旁边查找一个值,如果该值与我需要的值不匹配,则从该值向上移动一个单元格并检查是否匹配,等等。到目前为止我已经有了:
bits = []
for row in ws.iter_rows(row_offset=4,column_offset=3):
#skip over empty rows
if row:
#current cell is in column C
cell = row[2]
try:
#find the lowest address in the excel sheet
if cell.internal_value == min(address):
#somehow match up in column d
for '''loop and search col D''':
if str(row[3].internal_value).upper == ('CONTROL 1' or 'CON 1'):
#add bits
for cell in row[4:]:
bits.append(cell.internal_value)
#pass over cells that aren't a number, ie values that will never match an address
except ValueError:
pass
except TypeError:
pass
有办法做到这一点吗?我知道使用 row[3]
的比较在 D 列中进行比较,但如果第一次不正确,我不知道如何进入该列。或者换句话说,更改 row[value]
中的值在行中移动,我需要知道什么值/如何在列中移动。
谢谢!
最佳答案
bits = []
min_address = False
for row in ws.iter_rows(row_offset=4,column_offset=3):
c = row[2]
d = row[3]
if not d.internal_value: #d will always have a value if the row isn't blank
if min_address:
break #bits is what you want it to be now
bits = [] #reset bits every time we hit a new row
continue #this will just skip to next row
for bits_cell in row[4:]:
if bits_cell.internal_value:
bits.append(bits_cell.internal_value)
if c.internal_value:
if c.internal_value == min(address):
min_address = True #we set it to true, then kept going until blank row
关于python - 使用 openpyxl 移动到相邻单元格,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11162355/