python - 如何在 python 中循环具有子菜单的菜单？

Question

我正在尝试创建一个带有子菜单的主菜单。我想要做到这一点，以便无论用户从主菜单到子菜单选择什么顺序，他们最终都会被引导回主菜单 - 也就是说，直到他们选择最后一个选项(3.按住并结束转动) .

这就是我陷入困境的地方。目前，用户只能浏览一次菜单序列。如何使其成为重复循环？

#main menu
playermenumain=raw_input("What would you like to do?\n (1) Buy\n (2)Sell\n (3)Hold and end turn ")

if playermenumain=="1":

        buyermenu=raw_input("In what area would you like to buy?"\n (1)Stocks\n (2) Bonds\ (3) Nevermind\n)
        if buyermenu=="1":
            stockamount=stockamount+500
        elif buyermenu=="2":
            bondamount=bondamount+500
        else:
            buyermenu=raw_input("In what area would you like to buy?"\n (1)Stocks\n (2) Bonds\ (3) Nevermind\n) 

if playermenumain=="2":

    sellermenu=raw_input("In what area would you like to buy?"\n (1)Stocks\n (2) Bonds\ (3) Nevermind\n)
        if sellermenu=="1":
            stockamount=stockamount-500
        elif sellermenu=="2":
            bondamount=bondamount-500
        else:
            sellermenu=raw_input("In what area would you like to buy?"\n (1)Stocks\n (2) Bonds\ (3) Nevermind\n) 

if playermenumain=="3":

    break
#main menu loop: no matter what is selected, player is directed back to main menu until option 3 (end turn) is selected:

while playermenumain=="1" or playermenumain=="2":

        playermenumain=raw_input("What would you like to do?\n (1) Buy\n (2)Sell\n (3)Hold and end turn ")
        continue

Answer 1

尝试使用带有中断的 while True 循环而不是您拥有的 while 条件。例如:

def submenu_buy():
  # Put your submenus here
  pass

def submenu_sell():
  # Put your submenus here
  pass

while True:
  playermenumain=raw_input("What would you like to do?\n (1) Buy\n (2)Sell\n (3)Hold and end turn ")
  if playermenumain == "1":
    submenu_buy()
  elif playermenumain == "2":
    submenu_sell()
  elif playermenumain == "3":
    break