python - 我的代码可以工作，从某种意义上说，它运行我想要它执行的操作，但是一旦用户正确猜出数字，终端就会结束并且不会循环

Question

import random

number = random.randint(1,100)


while True:
    pick = input("Choose a number between 1 and 100. ")
    pick = int(pick)
    if pick == number:
        print("You are correct, great job! ")

    while True:
        if pick > number:
            print("That was too high of a guess. Try again. ")
            break       
        elif pick < number:
            print("That was too low of a guess. Try again. ")
            break

代码按照我希望的方式运行，但它在一次正确猜测后停止，并且我希望一旦用户正确猜测数字，循环就会重新启动

Answer 1

用一会一歇:

import random

number = random.randint(1,100)

while True:
    pick = int(input("Choose a number between 1 and 100. "))
    if pick == number:
        print("You are correct, great job! ")
        break # correct guess, break
    elif pick > number:
        print("That was too high of a guess. Try again. ")
    else: # one possibility left, so no need for another elif
        print("That was too low of a guess. Try again. ")

测试用例:

Choose a number between 1 and 100. 80
That was too high of a guess. Try again.
Choose a number between 1 and 100. 60
That was too high of a guess. Try again.
Choose a number between 1 and 100. 40
That was too low of a guess. Try again.
Choose a number between 1 and 100. 50
That was too low of a guess. Try again.
Choose a number between 1 and 100. 55
That was too high of a guess. Try again.
Choose a number between 1 and 100. 53
That was too low of a guess. Try again.
Choose a number between 1 and 100. 54
You are correct, great job!

如果您不希望它在正确猜测后停止，请删除中断，然后再次猜测:

import random

number = random.randint(1,100)

while True:
    pick = int(input("Choose a number between 1 and 100. "))
    if pick == number:
        print("You are correct, great job! ")
        number = random.randint(1,100) # guess again
    elif pick > number:
        print("That was too high of a guess. Try again. ")
    else: # one possibility left, so no need for another elif
        print("That was too low of a guess. Try again. ")