我正在使用这个答案here我有这段代码,它获取应变信号(2 个 channel ),然后应用校准步骤,然后打印 2 个 channel 和当前时间。但看起来打印与我在代码中使用的频率不匹配。
from time import sleep
from Phidget22.Phidget import *
from Phidget22.Devices.VoltageRatioInput import *
import time
import datetime
TIME_OUT = 5000 #5s beofre it throws a timeout exception
DATA_INTERVAL = 50 #50ms sample frequency
A0 = -6.128983223994E-06
B0 = -0.000059639277340
A1 = -6.101017778744E-06
B1 = -0.000286467338645
def onVoltageRatioChange0(self, voltageRatio):
Masse = (voltageRatio - (B0) ) / (A0)
self.masse = Masse
def onVoltageRatioChange1(self, voltageRatio):
Masse = (voltageRatio - (B1) ) / (A1)
self.masse = Masse
def results():
voltageRatioInput0 = VoltageRatioInput()
voltageRatioInput0.masse = 0
voltageRatioInput0.setChannel(0)
voltageRatioInput0.setOnVoltageRatioChangeHandler(onVoltageRatioChange0)
voltageRatioInput0.openWaitForAttachment(TIME_OUT)
voltageRatioInput0.setBridgeGain(BridgeGain.BRIDGE_GAIN_128)
voltageRatioInput0.setDataInterval(DATA_INTERVAL)
voltageRatioInput1 = VoltageRatioInput()
voltageRatioInput1.masse = 0
voltageRatioInput1.setChannel(1)
voltageRatioInput1.setOnVoltageRatioChangeHandler(onVoltageRatioChange1)
voltageRatioInput1.openWaitForAttachment(TIME_OUT)
voltageRatioInput1.setBridgeGain(BridgeGain.BRIDGE_GAIN_128)
voltageRatioInput1.setDataInterval(DATA_INTERVAL)
print(str(datetime.datetime.now()) + " / " + str(voltageRatioInput0.masse) + " / " + str(voltageRatioInput1.masse))
voltageRatioInput0.close()
voltageRatioInput1.close()
if __name__ == '__main__':
try:
while True:
results()
except KeyboardInterrupt:
print("Goodbye")
pass
因此,通常使用 VoltageRatioInput0.setDataInterval(DATA_INTERVAL)
它应该以 20 Hz 的频率打印该值。但它打印给我这个:
2019-11-22 10:24:59.460503 / -0.03847266852956798 / 0.2918630004986786
2019-11-22 10:25:00.099831 / -0.03695316689942101 / -0.02070779820379342
2019-11-22 10:25:00.772398 / -0.04029613574942367 / 0.28775155534154484
2019-11-22 10:25:01.420283 / -0.043487203384171676 / 0.25676361089420047
很明显,我没有 20 Hz...
最佳答案
您的 result()
函数可能花费了大量时间。我无法在这里重现,但一个简单的
python -m cProfile -s tottime your_program.py
应该可以帮助您了解每个循环迭代的大部分时间都花在哪里。
我认为实例化 VoltageRatioInput()
和 VoltageRatioInput.close()
是一个很好的开始方式。您可以尝试将它们放在循环之外,如下所示:
from Phidget22.Phidget import *
from Phidget22.Devices.VoltageRatioInput import *
import datetime
TIME_OUT = 5000 #5s beofre it throws a timeout exception
DATA_INTERVAL = 50 #50ms sample frequency
A0 = -6.128983223994E-06
B0 = -0.000059639277340
A1 = -6.101017778744E-06
B1 = -0.000286467338645
def onVoltageRatioChange0(self, voltageRatio):
Masse = (voltageRatio - (B0) ) / (A0)
self.masse = Masse
def onVoltageRatioChange1(self, voltageRatio):
Masse = (voltageRatio - (B1) ) / (A1)
self.masse = Masse
def results(voltageRatioInput0, voltageRatioInput1):
voltageRatioInput0.masse = 0
voltageRatioInput0.setChannel(0)
voltageRatioInput0.setOnVoltageRatioChangeHandler(onVoltageRatioChange0)
voltageRatioInput0.openWaitForAttachment(TIME_OUT)
voltageRatioInput0.setBridgeGain(BridgeGain.BRIDGE_GAIN_128)
voltageRatioInput0.setDataInterval(DATA_INTERVAL)
voltageRatioInput1.masse = 0
voltageRatioInput1.setChannel(1)
voltageRatioInput1.setOnVoltageRatioChangeHandler(onVoltageRatioChange1)
voltageRatioInput1.openWaitForAttachment(TIME_OUT)
voltageRatioInput1.setBridgeGain(BridgeGain.BRIDGE_GAIN_128)
voltageRatioInput1.setDataInterval(DATA_INTERVAL)
print(str(datetime.datetime.now()) + " / " + str(voltageRatioInput0.masse) + " / " + str(voltageRatioInput1.masse))
if __name__ == '__main__':
try:
voltageRatioInput0 = VoltageRatioInput()
voltageRatioInput1 = VoltageRatioInput()
while True:
results(voltageRatioInput0, voltageRatioInput1)
voltageRatioInput0.close()
voltageRatioInput1.close()
except KeyboardInterrupt:
print("Goodbye")
关于python - 打印不符合数据间隔设置,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58991319/