基本上，这段代码的目标是报告一组设备上的哪些端口正在被使用。
代码如下:
`$` file_name = input('Enter File Name: ') + str('.csv')
total_ports = 500
my_reader = csv.reader(open(file_name))
ctr = 0
for total_reserved in my_reader:
if total_reserved[2] == 'Reserved':
ctr += 1
print(ctr, 'out of ', total_ports, 'PLS ports are reserved')
my_reader = csv.reader(open(file_name))
ctr_pls0 = 0
for pls0 in my_reader:
if pls0[0] == 'L1 switches/L1 Switch 10G PLS0.BLLAB/Blade01' and total_reserved[2] == 'Reserved':
ctr_pls0 += 1
print(ctr_pls0, 'of these', ctr, 'are pls0 ports') `$`
这给了我以下输出...
Enter File Name: 31.05.2018
175 out of 500 PLS ports are reserved
0 of these 175 are pls0 ports
Process finished with exit code 0
0 of these 175 are pls0 ports这就是问题所在，这一行应该为我提供名为 'L1 switches/L1 Switch 10G PLS.BLLAB/Blade01' 的端口数量。 AND 显示为 'Reserved' 根据 .csv 文件。
你知道这可能是什么吗？
谢谢!
最佳答案
在第二个循环中，您应该使用 pls0[2]，而不是 total_reserved[2]。 total_reserved 包含第一个循环中文件的最后一行。
但是根本没有必要进行两个循环，只需在第一个循环中增加两个变量即可。
with csv.reader(open(file_name)) as my_reader:
ctr = 0
ctr_pls0 = 0
for total_reserved in my_reader:
if total_reserved[2] == 'Reserved':
ctr += 1
if total_reserved[0] == 'L1 switches/L1 Switch 10G PLS0.BLLAB/Blade01'
ctr_pls0 += 1
print(ctr, 'out of ', total_ports, 'PLS ports are reserved')
print(ctr_pls0, 'of these', ctr, 'are pls0 ports') `$`
关于python - 尝试使用 2 列，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/50628206/