php - 按频率对 SQL 查询记录排序

Question

有什么方法可以根据某个值在列中出现的频率来对您从 SQL 查询中选择的记录进行排序吗？例如:如果有五个记录 where column = 'value1'，三个 where column = 'value2'，两个 where column = 'value3'，有没有办法让结果先显示 'value1'，然后显示 'value2' , 最后是 'value3'?

Answer 1

SELECT   `column`,
         COUNT(`column`) AS `count`
FROM     `table`
GROUP BY `column`
ORDER BY `count` DESC

快速 PoC:

mysql> CREATE TABLE `table` (`id` SERIAL, `column` char(6) NOT NULL, KEY `column_idx`(`column`));
Query OK, 0 rows affected (0.01 sec)

mysql> INSERT INTO `table` (`column`) VALUES ('value1'), ('value1'), ('value1'), ('value1'), ('value1'), ('value2'), ('value2'), ('value2'), ('value3'), ('value3');
Query OK, 10 rows affected (0.00 sec)
Records: 10  Duplicates: 0  Warnings: 0

mysql> SELECT * FROM `table`;
+----+--------+
| id | column |
+----+--------+
|  1 | value1 |
|  2 | value1 |
|  3 | value1 |
|  4 | value1 |
|  5 | value1 |
|  6 | value2 |
|  7 | value2 |
|  8 | value2 |
|  9 | value3 |
| 10 | value3 |
+----+--------+
10 rows in set (0.00 sec)

mysql> SELECT   `column`,
    ->          COUNT(`column`) AS `count`
    -> FROM     `table`
    -> GROUP BY `column`
    -> ORDER BY `count` DESC;
+--------+-------+
| column | count |
+--------+-------+
| value1 |     5 |
| value2 |     3 |
| value3 |     2 |
+--------+-------+
3 rows in set (0.00 sec)