我正在尝试在 python 3.6 中编写一个函数,该函数返回一个字典,其中项目计数为键,以及具有该计数的项目列表。
以下是测试用例的示例: 输入:{'x':3,'y':3,'z':100} 输出:{3: ['x', 'y'], 100: ['z']}
这是我到目前为止的代码:
def get_count_items(key_count):
# create blank dictionary
count_items = {}
#for each item_key in key_count:
for item_key in key_count
# retrieve its value (which is a count)
# if the count (as key) exists in count_items:
if item in count_items:
count_items[item] += 1
# append the item_key to the list
# else:
#add the count:[item_key] pair to count_items dictionary
else:
count_items[item] = 1
for key, value in count_items.items():
#return count_items dictionary
return count_items
我的问题是如何将每个计数值设置为键,以及如何为具有该计数的每个项目创建相应的列表?
感谢您的帮助!
最佳答案
from collections import defaultdict
d = {'x':3, 'y':3, 'z':100}
# create defaultdict with list type.
res = defaultdict(list)
# iterate over key value pair
for k, v in d.items():
res[v].append(k)
print(res)
# or
print(dict(res))
输出:
defaultdict(<class 'list'>, {3: ['x', 'y'], 100: ['z']})
{3: ['x', 'y'], 100: ['z']}
关于python - 如何在 python 3.6 中创建带有值列表的频率字典,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58966451/