这是我的代码:
import math
print("Hey, lets solve Task 4 :)")
number1 = input("How many digits do you want to look at? ")
number2 = input("What would you like the digits to add up to? ")
if number1 == 1:
cow = range(0,10)
elif number1 == 2:
cow = range(10,100)
elif number1 == 3:
cow = range(100,1000)
elif number1 == 4:
cow = range(1000,10000)
elif number1 == 5:
cow = range(10000,100000)
elif number1 == 6:
cow = range(100000,1000000)
elif number1 == 7:
cow = range(1000000,10000000)
elif number1 == 8:
cow = range(10000000,100000000)
elif number1 == 9:
cow = range(100000000,1000000000)
elif number1 == 10:
cow = range(1000000000,10000000000)
number3 = cow[-1] + 1
n = 0
while n < number3:
number4 = list(cow[n])
n += 1
我希望制作一个循环,以便对于列表中的每个元素,它将被分解为每个字符。例如,假设数字 137
在列表中,然后将其变成 [1,3,7]
。然后,我想将这些数字添加在一起(我还没有开始这一点,但是我对如何做)。
但是,我一直收到此错误消息:
TypeError: 'int' object is not iterable
我做错了什么?
最佳答案
您的问题与此行:
number4 = list(cow[n])
它试图取 cow [n]
,它返回整数,并将其作为列表。如下所示,这无效:
>>> a = 1
>>> list(a)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'int' object is not iterable
>>>
也许您打算将 cow [n]
内部
number4 = [cow[n]]
请参阅下面的演示:
>>> a = 1
>>> [a]
[1]
>>>
另外,我想解决两件事:
要拆分数字,然后像您想要的那样添加它们,我首先将数字作为字符串。然后,由于字符串是可以的,因此您可以使用sum
:
>>> a = 137
>>> a = str(a)
>>> # This way is more common and preferred
>>> sum(int(x) for x in a)
11
>>> # But this also works
>>> sum(map(int, a))
11
>>>
关于Python -TypeError : 'int' object is not iterable,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19523563/